is there a way to take the result of a printf in a char array?
I need to set a string P: result
where result is an int
So if result = 4;
So I need a char array containing "S: 4"
Other methods are fine too, however I have my result in printf, so I wonder if I can just fetch it?
Yes, you can use snprintf (a safer alternative to sprintf). The only difference between snprintf and printf is that snprintf writes to a char * instead of directly to standard output:
#include <stdio.h> int main(int argc, char *argv[]) { char buffer[128]; int result = 4; snprintf(buffer, sizeof(buffer), "S: %d", result); printf("%s\n", buffer); return 0; } 
snprintf should be checked to see if a larger buffer was required, or some other error occurred.You can use sprintf to get the formatted string.
http://www.tutorialspoint.com/c_standard_library/c_function_sprintf.htm
sprintf. snprintf is better, since buffer overrun is caused by the programmer telling the function the buffer is bigger than it actually is.
snprintf() like in another answer is not much better than this answer. It trades a bad problem (potential buffer overflow in the general case) with an undetected wrong result. Using snprintf() too often conveys a false sense of "safety" when the result of snprintf() is not checked.sprintf() too so long as the buffer size is correct. The "which is not usually a showstopper" is the false sense of safety of my comment. char s[16], sprintf(s, sizeof s, "Target is %d %d", lat, lon); cmd(s); Agree snprintf() with result checking should be SOP.asprintf for that.
sprintf