python requests @ params

Question

I try to using request.get with '@' in params, but in output I have '%40' How I can decode this dict?

Using Python3

import requests payload = {'OPERATION-NAME': 'findItemsByProduct','productId.@type':'ReferenceID'} req = requests.post(url, params=payload) print(req.url)

The output is - 'url?productId.%40type=ReferenceID'

Using urllib.parse.unquote: unquote("url?productId.%40type=ReferenceID") returns 'url?productId.@type=ReferenceID'. What's wrong about that? — Daniel
– Daniel, Commented Dec 5, 2017 at 19:57
Heya, the comment section isn't for discussing new problems that arise. If you've solved it partially and are getting new exceptions, it's time to open a new question (after doing proper research!) :) — Daniel
– Daniel, Commented Dec 5, 2017 at 20:09

epinal · Accepted Answer · 2017-12-05 20:04:22Z

1

Use "data" argument instead of params. You should also specify the header, in this case json and then convert the payload dict to json using json.dumps().

import requests import json payload = {'productId.@type':'ReferenceID'} req = requests.post(url, headers={'Content-Type': 'application/JSON'}, data=json.dumps(payload)) print(req.url)

edited Dec 5, 2017 at 20:04

answered Dec 5, 2017 at 19:48

epinal

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7 Comments

Daniel Over a year ago

I see you answered OP, but didn't provide an explanation. Please include some context in your answer.

epinal Over a year ago

I forgot to include the header, try again and let me know. Make sure you have a valid url. BTW what you get is not the request (req) it's the response so you should rename req by resp.

TheRutubeify Over a year ago

TypeError: request() got an unexpected keyword argument 'header'

epinal Over a year ago

What python are you using? Pyhton2 / Python3, What requests version??

epinal Over a year ago

My bad it's 'headers' plural. I didn't test the code just writing from my head. It should work.

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