Remove all slashes and backsleshes [duplicate]

Question

I have a string:

res = 'qwer!@ 234234 4234gdf36/\////// // \ \\\$%^$% dsfg'

and I want to remove ALL slashes and backslashes. I tried this:

import string import re symbolsToRemove = string.punctuation res = 'qwer!@ 234234 4234gdf36/\////// // \ \\\$%^$% dsfg' res = re.sub(r'['+symbolsToRemove+']', ' ', res) print(res)

But get the next result:

qwer 234234 4234gdf36 \ \ \ dsfg

What am I doing wrong?

Can you not just do res.replace ("\\", "").replace ("/", "") — Minion Jim
– Minion Jim, Commented Feb 15, 2018 at 12:15
The resulting regex is [!"#$%&'()*+,-./:;<=>?@[\]^_{|}~]` and the \ escaspes a ] in it. You should escape the symbols to match literal chars. Or at least escape the -, ], ^ and \. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Feb 15, 2018 at 12:18
Replace works just fine. Don't bother with regular expressions. — Mathieu
– Mathieu, Commented Feb 15, 2018 at 12:19
@Mathieu i think we should encourage the use of regex, as they are fast and efficient — user5722540
– user5722540, Commented Feb 15, 2018 at 12:20
also related escaping regex string in python : '[' + re.escape(symbolsToRemove) + ']' — Nahuel Fouilleul
– Nahuel Fouilleul, Commented Feb 15, 2018 at 12:24

user5722540 · Accepted Answer · 2018-02-15 12:17:47Z

import string import re symbolsToRemove = string.punctuation res = 'qwer!@ 234234 4234gdf36/\////// // \ \\\$%^$% dsfg' res = re.sub(r'[\\]*[\/]*','', res) print(res)

anubhava · Accepted Answer · 2018-02-15 12:27:09Z

1

This should work with re.escape:

>>> print re.sub(r'['+re.escape(symbolsToRemove)+']+', ' ', res) qwer 234234 4234gdf36 dsfg

edited Feb 15, 2018 at 12:27

answered Feb 15, 2018 at 12:17

anubhava

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4 Comments

Thierry Lathuille Over a year ago

Yes, it does: >>> string.punctuation '!"#$%&\'()*+,-./:;<=>?@[\\]^_{|}~'`

anubhava Over a year ago

Sorry for the goof up. Yes OP just needs to do re.esacpe

Mikhail_Sam Over a year ago

I didn't get it - you previous answer did it well :) What's the matter to change it?

anubhava Over a year ago

@Mikhail_Sam: Previous answer also worked because it had separate \\ but I had wrong explanation. This one will also work because re.escape(symbolsToRemove) will escape each and every special character in symbolsToRemove string where \ is already present.

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