799

I need a way to get a dictionary value if its key exists, or simply return None, if it does not.

However, Python raises a KeyError exception if you search for a key that does not exist. I know that I can check for the key, but I am looking for something more explicit. Is there a way to just return None if the key does not exist?


See also: Why dict.get(key) instead of dict[key]?

3
  • 133
    Just use .get(key) instead of [key] Commented May 25, 2011 at 20:51
  • 3
    Accessing the key and catching the exception is perfectly okay in Python. It is even a well known and oft-used design pattern. If you return None instead, it becomes impossible to store None as a value, which may be relevant in some cases. Commented May 25, 2011 at 22:00
  • 1
    Sometimes you want to treat "None" entries in the dictionary and missing entries the same, in that case the accepted answer seems to do the job just fine. Commented Jul 5, 2015 at 17:02

17 Answers 17

1340

You can use dict.get()

value = d.get(key) 

which will return None if key is not in d. You can also provide a different default value that will be returned instead of None (unless the dict actually contains None as the value for this key):

value = d.get(key, "empty") 
Sign up to request clarification or add additional context in comments.

9 Comments

Note that the second variant with a default fallback will still return None if the key is explicitly mapped to None in the dict. If that's not what you want, you can use something like d.get(key) or "empty".
@cib: Good point, but the solution has a similar problem - if the key is mapped to any "falsy" value (like [], "", False, 0.0 or indeed None), then your solution would always return 0. If you expect Nones as values, you will have to do the if key in d: check explicitly.
@cib cheers for that, I couldn't work out what I was doing wrong here.
@TimPietzcker - can you please explain your answer? d.get(key) or "empty" in case of key being mapped to any 'falsy' values is "empty" if i am not mistaken.
@MiloMinderbinder: "empty" is returned if key is not a valid key in d. It has nothing to do with the value key is mapped to.
|
73

Wonder no more. It's built into the language.

 >>> help(dict) Help on class dict in module builtins: class dict(object) | dict() -> new empty dictionary | dict(mapping) -> new dictionary initialized from a mapping object's | (key, value) pairs ... | | get(...) | D.get(k[,d]) -> D[k] if k in D, else d. d defaults to None. | ... 

Comments

36

You should use the get() method from the dict class

d = {} r = d.get('missing_key', None) 

This will result in r == None. If the key isn't found in the dictionary, the get function returns the second argument.

1 Comment

You do not have to pass None explicitly. It is the default.
36

Use dict.get

Returns the value for key if key is in the dictionary, else default. If default is not given, it defaults to None, so that this method never raises a KeyError.

Comments

27

I usually use a defaultdict for situations like this. You supply a factory method that takes no arguments and creates a value when it sees a new key. It's more useful when you want to return something like an empty list on new keys (see the examples).

from collections import defaultdict d = defaultdict(lambda: None) print d['new_key'] # prints 'None' 

2 Comments

The problem with the defaultdict is that it will keep growing each time a non-existing element is requested.
This can also be the desired behavior, like when you're trying to build a nested dict with a loop.
26

If you want a more transparent solution, you can subclass dict to get this behavior:

class NoneDict(dict): def __getitem__(self, key): return dict.get(self, key) >>> foo = NoneDict([(1,"asdf"), (2,"qwerty")]) >>> foo[1] 'asdf' >>> foo[2] 'qwerty' >>> foo[3] is None True 

8 Comments

@marineau: As i mentioned in a comment to another answer, the problem with the defaultdict is that it will grow each time an element that is not yet in there is requested. This is not always desirable.
@BjörnPollex This is by far the elegant one, Any clue on how to extend this to support any depth? I mean making foo['bar']['test']['sss'] to return None instead of exception, After one depth it start giving TypeError instead of KeyError
@itsneo. You could build the entire structure of NoneDicts. This would help in case the KeyError would happen in the innermost object. Otherwise the problem is, that once you return a None object you can't subscribe it anymore. One ugly hack would be to return another object that tests like None. Beware however that this could lead to horrible bugs.
@BjörnPollex Is it okay to change return dict.get(self, key) to return super().get(key)? Then if I decide to use OrderedDict instead of dict, for example, I don't have to worry about changing multiple lines of code.
@Wood Yes, that would actually be much nicer!
|
14

A one line solution would be:

item['key'] if 'key' in item else None 

This is useful when trying to add dictionary values to a new list and want to provide a default:

eg.

row = [item['key'] if 'key' in item else 'default_value'] 

1 Comment

That's a very intriguing approach. Thanks for adding this answer. I'll definitely explore this for a use-case.
12

As others have said above, you can use get().

But to check for a key, you can also do:

d = {} if 'keyname' in d: # d['keyname'] exists pass else: # d['keyname'] does not exist pass 

2 Comments

I now see that you already know how to do this. I was going to delete my post, but I'll leave it for reference for others.
This approach usually requires the key to be looked-up twice when it's there, which is probably the reason for the get method.
10

You could use a dict object's get() method, as others have already suggested. Alternatively, depending on exactly what you're doing, you might be able use a try/except suite like this:

try: <to do something with d[key]> except KeyError: <deal with it not being there> 

Which is considered to be a very "Pythonic" approach to handling the case.

3 Comments

I would argument that this would violate the "explicit instead of implicit" principle, and make the intent unclear. Not to mention the fragility and verbosity.
@Haroldo_OK: I could not disagree more, it's very explicit.
I'm inclined to agree that this is actually a very explicit approach. While it does make for more lines of code (get() is effectively a single line), it IS very readable.
5

As mentioned elsewhere a possible issue with dct.get(key, default) is that, if key in dct but dct[key] is None, you get None not your default:

>>> dct = dict(foo=123, baz=None) >>> dct.get("foo", 0) 123 >>> dct.get("bar", 0) 0 >>> dct.get("baz", 0) >>> # where'd the value go? 

Since Python 3.8, using the "walrus operator" to create an assignment expression, you can handle this like:

>>> value if (value := dct.get("baz")) is not None else 0 0 

Comments

4

For those using the dict.get technique for nested dictionaries, instead of explicitly checking for every level of the dictionary, or extending the dict class, you can set the default return value to an empty dictionary except for the out-most level. Here's an example:

my_dict = {'level_1': { 'level_2': { 'level_3': 'more_data' } } } result = my_dict.get('level_1', {}).get('level_2', {}).get('level_3') # result -> 'more_data' none_result = my_dict.get('level_1', {}).get('what_level', {}).get('level_3') # none_result -> None 

WARNING: Please note that this technique only works if the expected key's value is a dictionary. If the key what_level did exist in the dictionary but its value was a string or integer etc., then it would've raised an AttributeError.

Comments

1

I was thrown aback by what was possible in python2 vs python3. I will answer it based on what I ended up doing for python3. My objective was simple: check if a json response in dictionary format gave an error or not. My dictionary is called "token" and my key that I am looking for is "error". I am looking for key "error" and if it was not there setting it to value of None, then checking is the value is None, if so proceed with my code. An else statement would handle if I do have the key "error".

if ((token.get('error', None)) is None): do something 

Comments

1

If you have a more complex requirement that equates to a cache, this class might come in handy:

class Cache(dict): """ Provide a dictionary based cache Pass a function to the constructor that accepts a key and returns a value. This function will be called exactly once for any key required of the cache. """ def __init__(self, fn): super() self._fn = fn def __getitem__(self, key): try: return super().__getitem__(key) except KeyError: value = self[key] = self._fn(key) return value 

The constructor takes a function that is called with the key and should return the value for the dictionary. This value is then stored and retrieved from the dictionary next time. Use it like this...

def get_from_database(name): # Do expensive thing to retrieve the value from somewhere return value answer = Cache(get_from_database) x = answer(42) # Gets the value from the database x = answer(42) # Gets the value directly from the dictionary 

Comments

-1

As mentioned an issue with dct.get(key, default) is that, if key exists but is mapped to a falsy value (e.g. None), you will get that value, not default.

If you want to return a default value even when key exists but is mapped to None, you can use this implementation:

class MyDict(dict): def myget(self, key, default=None): """Get value by key, return default if key is missing or is mapped to a falsy value.""" val = self.get(key, default) if val is None: val = default if isinstance(val, dict): val = MyDict(val) return val 

Let's see an use case.

Suppose you get external data from a third-party that looks like this:

d1 = {"name":"Mark", "belongings":{"bycicles":2, "cars":5, "trucks":2}} d2 = {"name":"Peter"} d3 = {"name":"John", "belongings":None} 

To get the number of cars that belongs to Mark, you would do:

d1.get("belongings").get("cars") # 5 

and this would correctly return 5.

But if you use this to get the number of Peter's cars:

d2.get("belongings").get("cars") # throws AttributeError: 'NoneType' object has no attribute 'get' 

you would get an Exception because d2 does not have a belongings key, so the first gest returns None.

To fix this, you would do:

d2.get("belongings", {}).get("cars", 0) # returns 0 

This owuld correctly returns 0.

Now let's get the number of John's cars:

d3.get("belongings", {}).get("cars", 0) # throws AttributeError: 'NoneType' object has no attribute 'get' 

This would throw an error because in d3 the key belongings is mapped to a None value, which is then returned.

Now let's use our implementation:

MyDict(d3).myget("belongings", {}).myget("cars", 0) # 0 

1 Comment

Clarified use case
-2
  1. d1={"One":1,"Two":2,"Three":3}

  2. d1.get("Four")

If you will run this code there will be no 'Keyerror' which means you can use 'dict.get()' to avoid error and execute your code

1 Comment

As it’s currently written, your answer is unclear. Please edit to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers in the help center.
-3

You can use try-except block

try: value = dict['keyname'] except IndexError: value = None 

Comments

-7

If you can do it with False, then, there's also the hasattr built-in funtion:

e=dict() hasattr(e, 'message'): >>> False 

1 Comment

please don't do that consider most upvoted

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.