How do I pass a member function to a function that expects a function pointer? [duplicate]

Question

I am using a library that expects a function pointer for a callback function but I would like to pass a member function to it.

The way to do this seems to be by using std::bind and passing the target() as a parameter to the function expecting the function pointer, but I must be doing something wrong.

#include <iostream> #include <functional> using namespace std; typedef void(__stdcall* ClassicFuncPtr)(int a, double b); void CallMyFunc(ClassicFuncPtr f) { f(1, 2.0); } class MyClass { public: void Test() { function<void(int, double)> f = bind(&MyClass::MemberFunc, this, placeholders::_1, placeholders::_2); CallMyFunc(*f.target<ClassicFuncPtr>()); // not working, i don't know why... } private: void MemberFunc(int a, double b) { cout << "a=" << a << ", b=" << b << '\n'; } }; int main() { MyClass c; c.Test(); }

The target() returns a nullpointer.

Make MemberFunction a static member function, and pass a pointer to it directly? Unless it's really using other members of the object, because then there's really no way to do it using the information you have provided. — Some programmer dude
– Some programmer dude, Commented Jun 29, 2021 at 8:29
The MemberFunction expects a this pointer. How are you going to pass it, even in principle? — Evg
– Evg, Commented Jun 29, 2021 at 8:31

Evg · Accepted Answer · 2021-06-29 10:04:31Z

The problem here is that a member function expects a "hidden" first argument that is a this pointer. Loosely speaking, a member function

void Func(int a, double b);

is equivalent to a free function

void Func(MyClass* this, int a, double b);

There is no way to pass a this pointer via ClassicFuncPtr, and std::function tricks won't help you here. target() doesn't do any magic, it just returns a pointer to the stored function if types match, and in your code they don't, that's why you get a null pointer. std::bind returns a functional object (that stores this inside), but a functional object is quite distinct from a function pointer and can't be converted into one.

Given that you can't change the callback type, there is a pretty ugly and fragile work-around that uses a static variable to store the value of this pointer. It should give you the idea of how to make it work, at least in principle.

class MyClass { public: void Test() { thisPtr = this; CallMyFunc(MemberFuncInvoker); } private: inline static MyClass* thisPtr; static void MemberFuncInvoker(int a, double b) { thisPtr->MemberFunc(a, b); } void MemberFunc(int a, double b) { std::cout << "a = " << a << ", b = " << b << '\n'; } };

Note that static member functions don't expect a hidden this argument and behave like free functions in this respect (due to the absence of this argument, you can't access non-static data members inside a static member function).

Demo

Typically, callbacks are accompanied with a void*-like parameter that can be used to pass a this pointer. For example, theEnumWindows function from WinAPI has the signature

BOOL EnumWindows(WNDENUMPROC lpEnumFunc, LPARAM lParam);

That lParam is passed to a callback

BOOL CALLBACK EnumWindowsProc(HWND hwnd, LPARAM lParam);

Then, inside a free (or static) callback function you could do:

reinterpret_cast<MyClass*>(lParam)->MyMemberFunction(hwnd);

nhatnq · Accepted Answer · 2021-06-29 09:20:20Z

It's not possible to do that.The type of pointer-to-member-function is different from pointer-to-function. For example:

It will be int (*)(int,double) if an ordinary function.
It will be int (MyClass ::*)(int,dobule) if a non-static member function of class MyClass

Note: In case that it’s a static member function, its type is the same as if it was an ordinary function int (*)(int,double).

In order to make it work somehow with the non-static member function. It also needs this pointer. Thus, you can rewrite the function as following

typedef void(MyClass::*ClassicFuncPtr)(int a, double b); void CallMyFunc(MyClass* t, ClassicFuncPtr f) { (t->*f)(1, 2.0); }

OP wrote that they uses a library. Changing a callback type might be impossible then.

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