getting the error traceback in a registered atexit function

Question

I am trying to log the error that caused my process to shut down, but traceback.print_tb and traceback.print_exc don't seem to realize what the raised error is.

In other words, why does the following print 'None\n' instead of 'DivisionByZero .. etc ..'? (Edit: ..and how do I get access to the raised/handled error from within exit_fn?)

import traceback, atexit def exit_fn(): print 'exiting' if traceback.format_exc().startswith('None'): print 'why is this None?' atexit.register(exit_fn) x = 1/0

This may help: stackoverflow.com/questions/9741351/…

e9t
– e9t

2015-06-29 09:16:07 +00:00
Commented Jun 29, 2015 at 9:16 — e9t
– e9t, Commented Jun 29, 2015 at 9:16

Scott Hunter · Accepted Answer · 2012-01-26 21:34:53Z

I believe that, by the time your routine has been called, the exception has already been 'handled' (at least when I run your code, I see a traceback even if I remove your call to print one), so that there is none to be formatted at that point.

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