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Python 2, 4847 bytes

A straight forward solution. The function expects 2 points as sequences of numbers, and returns the distance between them.

lambda a,b:sum((d-e)**2for d,e in zip(a,b))**.5

Example:

>>> f([13.37, 2, 6, -7], [1.2, 3.4, -5.6, 7.89]) 22.50202213135522

A straight forward solution. The function expects 2 points as sequences of numbers, and returns the distance between them.

lambda a,b:sum((d-e)**2for d,e in zip(a,b))**.5

Example:

>>> f([13.37,2,6,-7], [1.2,3.4,-5.6,7.89]) 22.50202213135522

A straight forward solution. The function expects 2 points as sequences of numbers, and returns the distance between them.

lambda a,b:sum((d-e)**2for d,e in zip(a,b))**.5

Example:

>>> f([13.37, 2, 6, -7], [1.2, 3.4, -5.6, 7.89]) 22.50202213135522

answered Jan 30, 2016 at 13:06

A straight forward solution. The function expects 2 points as sequences of numbers, and returns the distance between them.

lambda a,b:sum((d-e)**2for d,e in zip(a,b))**.5

Example:

>>> f([13.37,2,6,-7], [1.2,3.4,-5.6,7.89]) 22.50202213135522