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print(table); var ElementList = table.toList(3); print(ElementList); var i = 0; for(i=0;i<3;i++){ var element = ElementList.get(i); print(element); var dataset = ee.ImageCollection("COPERNICUS/S2_SR") .filterMetadata("CLOUD_COVERAGE_ASSESSMENT","less_than",20) .filterDate('2020-1-1','2021-1-1').filterBounds(element.geometry()) .map(maskS2clouds).map(add_MNDWI).map(add_NDVI).map(add_EVI).map(add_USI).map(add_UWI); print(dataset);

How to get the geometry of a feature? I searched the functions of Feature and found .geometry() as I wrote in the code, but I was told that this function is DEPRECATED and need to use Element.geometry() which I didn't know how to use it in my code.

table is a FeatureCollection and I turned it to a List, then get every Feature of it which is called element.

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Can you provide a working example so that we can replicate the error? Also using for loops like this is not recommended, so consider using .map() (https://developers.google.com/earth-engine/tutorials/tutorial_js_03).

Finally most likely because you loop client side you have to cast your element as a feature like this

print(table); var ElementList = table.toList(3); print(ElementList); var i = 0; for(i=0;i<3;i++){ var element = ee.Feature(ElementList.get(i)); print(element); var dataset = ee.ImageCollection("COPERNICUS/S2_SR") .filterMetadata("CLOUD_COVERAGE_ASSESSMENT","less_than",20) .filterDate('2020-1-1','2021-1-1').filterBounds(element.geometry()) .map(maskS2clouds).map(add_MNDWI).map(add_NDVI).map(add_EVI).map(add_USI).map(add_UWI); print(dataset)};

But hard to tell exactly without a working example!

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  • Thank you very much! I changed my code as you teached me and it worked now. I will update this question for you to repeat my error. Thank you. Commented Jan 24, 2022 at 17:10
  • Glad it worked, if you then could accept the answer for future reference Commented Jan 24, 2022 at 18:56

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