Extending an extension method? Or something?

Question

Sorry I'm not very clear. It's sort of hard to explain what I'm looking to do. I'd like to make extension methods but have them segregated. So for example...

bool b = true; char c = b.bool_ext.convert_to_YorN(); int i = b.bool_ext.convert_to_1or0();

Is something like that possible? Thanks!

@mellamokb I clearly stated it was an example. That being said, I surely hope your code isn't full of irrelevant comments... — Ber53rker
– Ber53rker, Commented Jul 21, 2012 at 0:54
@ThomasLevesque I think that might suit my needs. Could you provide an example? Thanks! — Ber53rker
– Ber53rker, Commented Jul 21, 2012 at 0:58

Scott Chamberlain · Accepted Answer · 2012-07-21 00:48:01Z

No that is not possible, The bool_ext would be a extension property of bool, and you can not currently do extension properties, only extension methods.

Ry- · Accepted Answer · 2012-07-21 01:40:38Z

If you want them "segregated", then you'd have to either invent your own type:

public struct MyBool { public MyBool(bool value) : this() { this.Value = value; } public bool Value { get; private set; } } public static MyBoolExtensions { public static char convert_to_YorN(this MyBool value) { return value.Value ? 'Y' : 'N'; } } public static BooleanExtensions { public static MyBool bool_ext(this bool value) { return new MyBool(value); } }

Which can be used like:

bool b = true; char c = b.bool_ext().convert_to_YorN();

Or just use them as static methods:

public class MyBoolConverters { public static char convert_to_YorN(bool value) { return value.Value ? 'Y' : 'N'; } }

Which can be used like:

bool b = true; char c = MyBoolConverters.convert_to_YorN(b);

But you cannot categorize them like you show.

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