I wish to understand if both Class.forName("ClassName") and ClassObject.getClass return runtime instance of the class. Then why on comparing the resulting Class object obtained from the two fetches us a Boolean false(if we compare using == or equals).
I also want to know what is the exact use of .class method called on the class name.I have read that it is determined at compile time etc but to what purpose. Won't Class.forName("ClassName") suffice??
Thanks
2 Answers
Yes, they are the same - and they return the exact same object.
Example:
public class Tryout { public static class A { } public static class B extends A { } public static void main(String[] args) throws Exception { A a = new A(); A b = new B(); //the same class object, one achieved statically and one dynamically. System.out.println(a.getClass() == A.class); //the same class object using forName() to get class name dynamically System.out.println(Class.forName("Tryout$A") == A.class); //different class. B is not A! System.out.println(b.getClass() == A.class); } } Will yield:
true true false Note that the last is yielding false because - though the static type is the same, the dynamic type of B is NOT A, and thus getClass() returns B, which is the dynamic class object of b.
Class.forName("ClassName")attempts resolution at runtime and throw an exception if not found, whileClassName.classwill either prevent the class from passing verification or compilation entirely.