Else block in Python code keeps throwing invalid syntax error...no matter what I do to correct it

Question

I am not an expert Pythonista per se so I will begin with that as a clarification for me asking what could be a considered a trivial question about an else statement issue I have. Anyway for the sake of brevity, I went through all of the else syntax questions on stackoverflow regarding the same/similar issues and I was still unable to resolve the problem. Here is the code block in question:

 else: m_len -= 33 dst.append(32) n, m_len = divmod(m_len, 255) dst.extend("\x00" * n) dst.append(m_len) dst.append((m_off << 2) & 0xff) dst.append((m_off >> 6) & 0xff) else: #This is the line being complained about m_off -= 0x4000 if m_len <= 9: dst.append(0xff & (16 | ((m_off >> 11) & 8) | (m_len - 2)))

Thanks in advance for any help or advise that can be offered! Cheers!

Insidi0us · Accepted Answer · 2012-10-16 02:08:32Z

You can't have more than one else statement in a single conditional block
Change the first else to elif and specify some condition

Arnaud Aliès · Accepted Answer · 2012-10-16 10:47:19Z

You conditions must be like that:

if (condition):#the program can choose as many "if" as many you put in your program (in theory) ..code.. #here you can add as many "if" as you want elif (condition):#the program will only choose one block you must have a "if" block before ..code.. #here again you can add as many "elif" as you want else:#before "else" you must have a if block before ..code.. #here only one "else"

how do you think the program could choose else or else?! lol

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