Why am I getting a syntax error on this else if statement?

Question

I'm writing a code for a dice roll game and getting a weird syntax error. The syntax error I get for the script below is: invalid syntax: else: ^

import random num = random.randint(1, 7) def dice_roll(): gold = 0 input = ('Do you want to play again?' ) if num == 2: gold = (gold + 2) print (gold) print ('You Win!') print (input) if input != ('yes'): dice_roll() else: print ('Loser') dice_roll()

Does someone know why this code would give me such an error?

Andreas · Accepted Answer · 2018-11-05 00:17:42Z

Python is particular about indentation. Your else statement should have equal indentation as the above if-statement.

 if input != ('yes'): dice_roll() else: print ('Loser')

Mikhail Berlinkov · Accepted Answer · 2018-11-05 00:10:41Z

0

Else must be aligned with if, that is, shift two last lines to the left so that "else" was right under if.

answered Nov 5, 2018 at 0:10

Mikhail Berlinkov

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1 Comment

Adag89 Over a year ago

Thanks I got it working, and understand the theory a little better now.

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