Erasing from a pointer to a vector of pointers

Question

For the following code:

vector<int*> x; vector<int*>* p; // say I initiated x with a couple of integers p = &x; //erases the indicie of the given integer void erase(vector<int*> &x, int n){ int i = 0; while (*(x[i]) != n){ i++; } delete x[i]; x.erase(x.begin() + i); }

If I call the code erase(*p, 2); I want to now set p to this address of this vector that has been erased ... I'm trying p = &(*p); .. but that doesn't work and I get a segmentation fault, any ideas?

You need to explain it better. It is completely unclear at this point. "i want to now set p to this address of this vector that has been erased" - what is that supposed to mean? No vector is erased in your code and there's no reason to do anything with p. — AnT stands with Russia
– AnT stands with Russia, Commented Nov 20, 2012 at 19:59
basically want p to be the address of this new vector, since erase took that vector and removed a certain indicie. — John Smith
– John Smith, Commented Nov 20, 2012 at 20:17
@JohnSmith, there is no new vector. The old vector is the only vector. It persists through the call to erase. — Robᵩ
– Robᵩ, Commented Nov 20, 2012 at 20:18

John Kugelman · Accepted Answer · 2012-11-20 20:00:11Z

2

You shouldn't have to do anything. p still points to &x just as it did before you called erase(). Removing an element from a vector doesn't change the address of the vector.

answered Nov 20, 2012 at 20:00

John Kugelman

365k70 gold badges555 silver badges600 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

John Smith Over a year ago

so after i call erase (*p, 2), p will now be the address of the vector of a shorter vector. ?

Robᵩ Over a year ago

p will be unchanged, and will continue to point to x. You only have one vector, there is no "shorter vector".

Collectives™ on Stack Overflow

Erasing from a pointer to a vector of pointers

1 Answer 1

2 Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Related