I am composing a program which allows me to calculate a person's age in days- accounting for every day including leap days, and irregular number of days in months. Here is a line of code:
number_of_days = (((year2 - year1) * 12) + (month2 - month1)) * 30.4375 + (day2 - day1) I got the value 30.4375 by dividing 365.25 by 12.
Now I only need to store the integer part in number_of_days. How do I do that?
Help is really appreciated!
P.S. All variable values are int values
You can either use int:
number_of_days = int((((year2 - year1) * 12) + (month2 - month1)) * 30.4375 + (day2 - day1)) or math.floor:
import math number_of_days = math.floor((((year2 - year1) * 12) + (month2 - month1)) * 30.4375 + (day2 - day1)) But then number_of_days will be a float, so I think the first solution is better.
Just call int:
number_of_days = int((((year2 - year1) * 12) + (month2 - month1)) * 30.4375 + (day2 - day1)) consider to use round instead of converting that is more accurate:
import math int(math.round((((year2 - year1) * 12) + (month2 - month1)) * 30.4375 + (day2 - day1))) 
Could you just use the floor function?
number_of_days = math.floor((((year2 - year1) * 12) + (month2 - month1)) * 30.4375 + (day2 - day1)) If your goal is to calculate the number of days between dates you can use the datetime module:
import datetime birth = datetime.date(1967,11,14) today = datetime.date.today() number_of_days = (today - birth).days 