Curl Equivalent in Python

Many folks turn to the requests library for this sort of thing.

For something lower level, you might use urllib2

I've been using the requests package as well. Here's an example POST from the requests documentation.

If you are feeling that you want to use CURL, try PyCurl.
Install it using:

sudo pip install pycurl

Here is an example of how to send data using it:

import pycurl import json import urllib import cStringIO url = 'your_url' first_param = '12' dArrayData = [{'data' : 'first'}, {'data':'second'}] json_to_send = json.dumps(dArrayData, separators=(',',':'), sort_keys=False) curlClient = pycurl.Curl() curlClient.setopt(curlClient.USERAGENT, 'curl-user-agent') # Sets the url of the service curlClient.setopt(curlClient.URL, url) # Sets the request to be of the type POST curlClient.setopt(curlClient.POST, True) # Sets the params of the post request send_params = 'first_param=' + first_param + '&data=' + urllib.quote(json_to_send) curlClient.setopt(curlClient.POSTFIELDS, send_params) # Setting the buffer for the response to be written to bufResponse = cStringIO.StringIO() curlClient.setopt(curlClient.WRITEFUNCTION, bufResponse.write) # Setting to fail on error curlClient.setopt(curlClient.FAILONERROR, True) # Sets the time out for the connections curlClient.setopt(pycurl.CONNECTTIMEOUT, 25) curlClient.setopt(pycurl.TIMEOUT, 25) response = '' try: # Performs the operation curlClient.perform() except pycurl.error as err: errno, errString = err print '========' print 'ERROR sending the data:' print '========' print 'CURL error code:', errno print 'CURL error Message:', errString else: response = bufResponse.getvalue() # Do what ever you want with the response.. Json it or what ever.. finally: curlClient.close() bufResponse.close() 

The requests library is most supported and advanced way to do this.