Here's the first exception coding I've ever done and guess what, it's generating an error. Sad.
public class Exc { int x = 2; public void throwE(int p) throws Excp { if(x==p) { throw new Excp(); } } } I don't think I need to post the handler code as even this class isn't getting through compiler.
I'm getting the error cannot find symbol at Excp. I'm doing exactly according book. Is there something I'm missing?
You are probably missing an Excp class. Try replacing Excp with Exception, for starters.
Excp is not a class from the Java Standard Library. Exception is. If you want to throw your own exception, such as Excp or MyException or WhateverNameYouWant you have to create such class and it has to extend Exception class. You can do so creating a new class like this: public class MyException extends Exception { //here the implementation}
Exc but you are throwing an Excp, so the compiler can't find anything actually called Excp and is complaining.