How to select the complete word within the brackets even if it have that brackets within word

Question

Give some solution to this following example,

Scenario-1:

My String : Password={my_pswd}}123}

I want to select the value enclosed within the {} brackets(Example: I want to select the complete password key value {my_pswd}123} not {my_pswd})

If I'm using this regex \{(.*?)\} , this will select {my_pswd} not {my_pswd}}123}. So how to get complete word even if the word has } in between? Give me some suggestions by using regex or any other way.

Scenario-2: I am using this regex ^\{|\}$ . If my string have both { bracket and } bracket like this {{my_password}} then only it want to select first and last bracket. If my string like this {{my_password, it don't want to select that starting bracket. Its like AND condition in Regex. I referred many posts they did with look up but I can't get clear idea. Give me some suggestion.

Thanks.

Comments are not for extended discussion; this conversation has been moved to chat. — user3956566
– user3956566, Commented Jul 1, 2018 at 2:16
See my answer, there is a demo, everything works as expected. If you test the patterns anywhere at online testers, use ^\{([\s\S]*)\}$ or /^\{(.*)\}$/gs — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 1, 2018 at 5:19
You are using the wrong option at regex101.com, why at all are you using it? See regex101.com/r/qCwcfi/2 with the JS option selected, it shows the regex works well for that right flavor. And see ideone.com/5wgIzu, it proves the regex is working with std::regex. — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Jul 1, 2018 at 6:12
@WiktorStribiżew, Thanks for your clear explanation. Now I got it and solved. — Piraisudan M
– Piraisudan M, Commented Jul 2, 2018 at 7:59

Wiktor Stribiżew · Accepted Answer · 2018-06-30 17:59:15Z

It seems that the {...} substrings you want to match must be followed with ; or end of string. This will not work for cases when a } inside the values can also be followed with ;.

You may solve the first issue by adding a (?![^;]) lookaround:

\{(.*?)\}(?![^;])

See the regex demo.

Details

\{ - a { char
(.*?) - Group 1: any 0+ chars as few as possible
\} - a } char
(?![^;]) - no char other than ; is allowed right after the current position

See the C++ demo:

#include <iostream> #include <vector> #include <regex> int main() { const std::regex reg("\\{(.*?)\\}(?![^;])"); std::smatch match; std::string s = "Username={My_{}user};Password={my_pswd}}123}}}kk};Password={my_pswd}}123}"; std::vector<std::string> results( std::sregex_token_iterator(s.begin(), s.end(), reg, 1), // See 1, it extracts Group 1 value std::sregex_token_iterator()); for (auto result : results) { std::cout << result << std::endl; } return 0; }

Output:

My_{}user my_pswd}}123}}}kk my_pswd}}123

As for the second scenario, you may use

std::regex reg("^\\{([^]*)\\}$"); std::string s = "{My_{}user}"; std::cout << regex_replace(s, reg, "$1") << std::endl; // => My_{}user

See another C++ demo.

The \{([^]*)\}$ pattern matches the { at the start (^) of the string, then matches and captures into Group 1 (later referenced with the help of $1 in the replacement pattern) any 0+ chars, as many as possible, and then matches a } at the end of the string ($).

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