Javascript: Deeply Changing a const array?

Question

I'm working on a problem that is expecting a const array to deeply equal a new set of values.

How would I go about this?

Instructions: Iterate through the array and multiply a number by 10 if it is greater than or equal to 5.

What I have:

const timesTenIfOverFive = [23, 9, 11, 2, 10, 6]; for(var i = 0; i < timesTenIfOverFive.length; i++){ if (timesTenIfOverFive[i] >= 5) { console.log(timesTenIfOverFive[i]*10); } else console.log(timesTenIfOverFive[i]); } // console.log(timesTenIfOverFive); // -> should print [230, 90, 110, 2, 100, 60]

equal a new set of values : const result = timesTenIfOverFive.map(e => e >= 5 ? e * 10 : e) — Taki
– Taki, Commented Jul 8, 2018 at 2:52
‘const’ doesn’t give an immutable value, it gives an immutable assignment, with which you cannnot reassign the variable, but still able to manipulate non-primitive data structure (object, array, etc) — Leonid Pyrlia
– Leonid Pyrlia, Commented Jul 8, 2018 at 9:26

CertainPerformance · Accepted Answer · 2018-07-08 02:50:49Z

const only means that the variable in question can't be reassigned - you can still mutate it. (Non-primitives, like objects and arrays, can be mutated.) The question is asking you to iterate over the array and mutate it, which is pretty easy with a for loop or forEach - on each iteration, assign the result to timesTenIfOverFive[i]:

const timesTenIfOverFive = [23, 9, 11, 2, 10, 6]; for(var i = 0; i < timesTenIfOverFive.length; i++){ if (timesTenIfOverFive[i] >= 5) { timesTenIfOverFive[i] *= 10; } } console.log(timesTenIfOverFive);

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