Why is AJAX call ignored?

Question

I don't know why the process ignores my AJAX call. It simply jumps from console.log("1"); to console.log("2");.

Can someone explain to me what is going wrong?

render: function() { let view = this; component.prototype.render.call(view); console.log("1"); $.ajax = ({ type: "GET", cache: false, url: "news.json", dataType: "json", success: function(json) { console.log("success"); for (let i = 0; i < json.length; i++) { let news = modelNews; news.title = json[i].title; news.type = json[i].type; news.img = json[i].img; news.link = json[i].link; view.$('#newsfeed').append(news.getNewsFeedLook()); } }, error: function() { console.log("error"); } }); console.log("2"); }

You need to call the $.ajax function, here you are assigning to it: $.ajax = ({ ... — Jean-Alphonse
– Jean-Alphonse, Commented May 22, 2019 at 13:54

MKougiouris · Accepted Answer · 2019-05-22 13:57:40Z

Your code is not calling the ajax function of jQuery, it is reassigning it.

$.ajax = ({ type: "GET", cache: false, url: "news.json", dataType: "json", success: function(json) { console.log("success"); for (let i = 0; i < json.length; i++) { let news = modelNews; news.title = json[i].title; news.type = json[i].type; news.img = json[i].img; news.link = json[i].link; view.$('#newsfeed').append(news.getNewsFeedLook()); } }, error: function() { console.log("error"); } });

This is the proper call, a function call that is. Pay closer attention to minor error like this!

$.ajax({ type: "GET", cache: false, url: "news.json", dataType: "json", success: function(json) { console.log("success"); for (let i = 0; i < json.length; i++) { let news = modelNews; news.title = json[i].title; news.type = json[i].type; news.img = json[i].img; news.link = json[i].link; view.$('#newsfeed').append(news.getNewsFeedLook()); } }, error: function() { console.log("error"); } });

Thank you. That helped. I just trusted too much IntelliJ code representation.

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