how do i handle Client error handling in python

Question

i am new at this and here is a piece my code:

with open('Accounts.txt') as f: account_list = f.readlines() for account in account_list: while account_list: try: account = account.rstrip('\n') #strip end of account in accounts.txt assume_response = sts_default_role.assume_role( RoleArn = f'arn:aws:iam::{account}:role/user/user.infosec', RoleSessionName = 'test_session', ) print(f"Logged in to {account}"), print("test first short loop") break except ClientError: print(f"Couldn't login to {account}"), break assume_creds = assume_response['Credentials'] session = boto3.session.Session( aws_access_key_id=assume_creds['AccessKeyId'], aws_secret_access_key=assume_creds['SecretAccessKey'], aws_session_token=assume_creds['SessionToken'], ) print("test outside the loop")

Here is my output:

Logged in to 733443824660 test first short loop test outside the loop Couldn't login to 111111222211 test outside the loop

as you can see it works great, the only problem i have is that once i hit an exception where i cant log in to an account i do not want the code to go further, because it does not make sense for it to go further and print (test outside the loop) comment when you cant log in to the account.

Any thoughts?

Does this answer your question? How to break out of multiple loops? — mkrieger1
– mkrieger1, Commented Mar 27, 2020 at 21:17

Anastasiia · Accepted Answer · 2020-03-27 23:07:44Z

0

If you would like to break execution of this program when you can not login into account, then it's better to exit:

import sys sys.exit()

This command will exit from your python script.

break command will only break execution of the inner loop. To break the outer loop, you will have to use break command again.

But if you can not login into one account from the list, maybe you will be able to login to any of the other ones.

answered Mar 27, 2020 at 23:07

Anastasiia

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7 Comments

NewDeveloper Over a year ago

Thanks Anastasiia, but:

NewDeveloper Over a year ago

When i add sys.exit() see below, my output is still not the same as i wanted to be:

NewDeveloper Over a year ago

try: account = account.rstrip('\n') #strip end of account in accounts.txt assume_response = sts_default_role.assume_role( RoleArn = f'arn:aws:iam::{account}:role/user/user.infosec', RoleSessionName = 'test_session', ) print(f"Logged in to {account}"), print("test first short loop") break except ClientError: print(f"Couldn't login to {account}"), sys.exit()

NewDeveloper Over a year ago

Logged in to 733447824660 test first short loop Couldn't login to 111111222211

NewDeveloper Over a year ago

you are right if i cant log in to account i want to proceed to try to log in to next account

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Anastasiia · Accepted Answer · 2020-03-29 15:30:05Z

Can suggest to remove second loop to loop through all accounts in the list:

with open('Accounts.txt') as f: account_list = f.readlines() for account in account_list: try: account = account.rstrip('\n') #strip end of account in accounts.txt assume_response = sts_default_role.assume_role( RoleArn = f'arn:aws:iam::{account}:role/user/user.infosec', RoleSessionName = 'test_session', ) print(f"Logged in to {account}"), print("test first short loop") continue # to go to the next round of the loop except ClientError: print(f"Couldn't login to {account}"), break # this block will be not executed print("test outside the loop") # will not be called if exception occurs

"Logged in to 733447824660 test first short loop Couldn't login to 111111222211" Not sure that this is what we want.
Unfortunately, I have no idea how to fix your code without knowing what should it do and how should it work. If my answers are not working for you and you would like to get more help, please specify how exactly should your code work.

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