use a lambda to start a thread which is a class attribute

Question

I would like to assign a name to a thread, the thread itself must do this. The thread is a class member of the class foo. I would like to start this thread with a lambda but unfortunately I get the error message: no match for call to '(std::thread) (foo::start()::<lambda()>)

Can someone explain to me where the problem is? Previously I had created a temporary thread object, and put this with move on the thread "manage", however, I can then give no name.

class foo { public: int start() { this->manage([this](){ auto nto_errno = pthread_setname_np(manage.native_handle(),"manage"); // Give thread an human readable name (non portable!) while(1){ printf("do work"); } }); return 1; } private: int retVal; std::thread manage; };

Omer Kawaz · Accepted Answer · 2022-03-17 07:54:11Z

You passed the lambda in a wrong way, after initialization the manage thread can't be initialized again. you should create a new std::thread and assign it. the following compiles and indeed prints "manage".

class foo { public: int start() { manage = std::thread([this]{ auto nto_errno = pthread_setname_np(manage.native_handle(),"manage"); char name[16]; pthread_getname_np(pthread_self(), &name[0], sizeof(name)); cout << name << endl; }); manage.join(); return 1; } private: int retVal; std::thread manage; };

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