2

Currently strugging with nicely printing a array of "O"'s, where the columns and rows should be numbered.

So I have a array which is just a nxn-matrix full of the string "O". Now I tried using the following method:

 def __repr__(self) : Matrix = self.Spielstand #this is just the mentioned array of length n: Ausgabe = " " for j in range(len(Matrix[0])): Ausgabe += str(j + 1) + " " Ausgabe += "\n" for i in range(len(Matrix)): Ausgabe += str(i + 1) + " " for j in range(len(Matrix[i])): Ausgabe += str(Matrix[i][j]) Ausgabe += " " Ausgabe += "\n" return Ausgabe

Which works perfectly fine printing something like:

 1 2 3 4 5 6 7 8 1 O O O O O O O O 2 O O O O O O O O 3 O O O O O O O O 4 O O O O O O O O 5 O O O O O O O O 6 O O O O O O O O 7 O O O O O O O O 8 O O O O O O O O

However when my n gets bigger than 9, things get kind of weird:

 1 2 3 4 5 6 7 8 9 10 1 O O O O O O O O O O 2 O O O O O O O O O O 3 O O O O O O O O O O 4 O O O O O O O O O O 5 O O O O O O O O O O 6 O O O O O O O O O O 7 O O O O O O O O O O 8 O O O O O O O O O O 9 O O O O O O O O O O 10 O O O O O O O O O O

Is there a simple and nice way (preferably without using external libraries) to print the array nicely even if my n is double or even triple digit? I think using f-Strings and something going from center should work, but I have no clue how to implement it. Thanks for your help!

Improve this question
1
  • Do you just want to figure out the maximum number of digits, then pad with spaces, as discussed in this post? Commented Sep 12, 2023 at 9:51

2 Answers 2

Reset to default
2

You can calculate margin size by counting the length of the number converted to string.

Margin = len(str(len(Matrix))) 
Martix -> (array of 12 "O") len(Martix) -> 12 str(12) -> "12" len("12") -> 2

I have created demo, with a solution to your problem:

def generateMatrix(n): return [["O"] * n] * n def draw(n): Matrix = generateMatrix(n) Margin = len(str(len(Matrix))) Ausgabe = " " * (Margin + 1) for j in range(len(Matrix[0])): Ausgabe += str(j + 1) + " " * (Margin - len(str(j+1)) + 1) Ausgabe += "\n" for i in range(len(Matrix)): Ausgabe += str(i + 1) + " " * (Margin - len(str(i+1)) + 1) for j in range(len(Matrix[i])): Ausgabe += str(Matrix[i][j]) Ausgabe += " " * Margin Ausgabe += "\n" return Ausgabe print(draw(12)) 
 1 2 3 4 5 6 7 8 9 10 11 12 1 O O O O O O O O O O O O 2 O O O O O O O O O O O O 3 O O O O O O O O O O O O 4 O O O O O O O O O O O O 5 O O O O O O O O O O O O 6 O O O O O O O O O O O O 7 O O O O O O O O O O O O 8 O O O O O O O O O O O O 9 O O O O O O O O O O O O 10 O O O O O O O O O O O O 11 O O O O O O O O O O O O 12 O O O O O O O O O O O O
Improve this answer
Sign up to request clarification or add additional context in comments.

Comments

1

You could probably do something with f strings and then force every value to be displayed to the same width.

f'{value:{width}.{precision}}'

https://stackoverflow.com/a/50340297/9050785

Improve this answer

Comments

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.