I need help with regex. I need to create a rule that would preserve everything between quotes and exclude quotes. For example: I want this...
STRING_ID#0="Stringtext"; ...turned into just...
Stringtext Thanks!
- 3More info needed: Can there be more than one quoted string in your input? Can there be escaped quotes? Which regex engine are you using?Tim Pietzcker– Tim Pietzcker2011-11-03 16:16:07 +00:00Commented Nov 3, 2011 at 16:16
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4 Answers
The way to do this is with capturing groups. However, different languages handle capturing groups a little differently. Here's an example in Javascript:
var str = 'STRING_ID#0="Stringtext"'; var myRegexp = /"([^"]*)"/g; var arr = []; //Iterate through results of regex search do { var match = myRegexp.exec(str); if (match != null) { //Each call to exec returns the next match as an array where index 1 //is the captured group if it exists and index 0 is the text matched arr.push(match[1] ? match[1] : match[0]); } } while (match != null); document.write(arr.toString()); The output is
Stringtext 
2 Comments
Kiechlus
You can do this shorter: let result = []; let regex = /myRegex/g; let match = regex.exec(data); while(match) { result.push(match[1]); match = regex.exec(data); }
SlickRemix
Best answer because it does not produce errors in Safari either, since this regex does not use lookahead or lookbehind.
Try this
function extractAllText(str) { const re = /"(.*?)"/g; const result = []; let current; while ((current = re.exec(str))) { result.push(current.pop()); } return result.length > 0 ? result : [str]; } const str =`STRING_ID#0="Stringtext"` console.log('extractAllText',extractAllText(str)); document.body.innerHTML = 'extractAllText = '+extractAllText(str);
Comments
"([^"\\]*(?:\\.[^"\\]*)*)" I recommend reading about REGEXes here
2 Comments
Tim Pietzcker
That doesn't remove the quotes from around the string.
Joao Figueiredo
Ouch, don't know how I forgot about it. But Tim Pietzcker is right, user should specify the REGEX engine
