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I have a series of preview images and RAW files in a directory structure (shown below), I quickly review the preview images, and delete those that I don't want.

The RAW files are in a RAW subdirectory of each directory.

What I'm looking for is a bash command, or small script that will delete the RAW file, if a file with the corresponding preview image doesn't exist.

The subdir tree looks like:

2016/ 05/ image1.jpg image2.jpg image3.jpg RAW/ image1.RAW image2.RAW image3.RAW

As you can imagine there are multiple year and month subdirectories, occasionally if there's been a large event, there may be a further set of subdirs below the month subdir, (as shown below) so ideally I'm looking for something I can chuck into cron to run once a day/week to just tidy up after any review/changes I make.

2016/ 05/ image1.jpg image2.jpg image3.jpg RAW/ image1.RAW image2.RAW image3.RAW event 1/ image4.jpg image5.jpg image6.jpg RAW/ image4.RAW image5.RAW image6.RAW event 2/ image7.jpg image8.jpg image9.jpg RAW/ image7.RAW image8.RAW image9.RAW
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  • Have you tried looking at cut to trim off the extension and just try an if statement to test if a file starting with the same name exists? Commented Jun 17, 2016 at 17:48
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    Show us what you've done so far and we'll help you complete it. Note that I would use sed s/.jpg/.RAW/ for the filename change and a few loops to deal with the directory structure. Commented Jun 17, 2016 at 18:00
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    @JuliePelletier If you're going to sed the extensions, better to use sed s/\.jpg$/.RAW/ to escape the wildcard . and to make sure you only match on the end of a filename. Commented Jun 17, 2016 at 18:26

4 Answers 4

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The easier will be the Costas way without any scripting but using builtin, proper dir and proper command substitution. (not tested)

find 2016 -name '*.RAW' -execdir sh -c '[ ! -f "../${0%.RAW}.jpg" ]' {} \; -delete

Writing a bash script doing this is trivial, some globstar (**) and some [[]] and done!

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  • No, that doesn't work. You're testing for the existence of the first file only, and then deleting them all. Commented Jun 18, 2016 at 19:57
  • Sure, I've test it and even Costa's way doesn't work. I've created the script and the test. It's really a shame that I didn't test it. Sorry about that. Commented Jun 19, 2016 at 10:49
  • perfect for deleting duplicate compiled typescript files :D Commented Oct 1, 2018 at 13:25
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Tested and working. 

#!/usr/bin/env bash #delete RAW if Preview img doesn't exists createTest() { local dir=$1 rm -rf "$dir" mkdir -p "$dir"/05/{"event 1","event 2"}/RAW/ mkdir -p "$dir"/05/RAW touch "$dir"/05/RAW/image{1..3}.RAW; touch "$dir"/05/image{1..2}.jpg touch "$dir/05/event 1/RAW/"image{4..6}.RAW; touch "$dir/05/event 1/"image{4..5}.jpg touch "$dir/05/event 2/RAW/"image{7..9}.RAW; touch "$dir/05/event 2/"image{7..8}.jpg } deleteRAW() { local jpg= local t= shopt -s globstar; for raw in "$1"/**/*.RAW; do t=${raw##*/} jpg=${raw%/*}/../${t%.*}.jpg if [[ ! -f $jpg ]]; then rm -f "$raw" echo "Removed $raw" fi done; } for dir; do createTest "$dir" deleteRAW "$dir" done

Testing:

]➬./delete.sh 2016 Removed 2016/05/RAW/image3.RAW Removed 2016/05/event 1/RAW/image6.RAW Removed 2016/05/event 2/RAW/image9.RAW

Testing with spaces: 

]➬./delete.sh "2016 spaces" Removed 2016 spaces/05/RAW/image3.RAW Removed 2016 spaces/05/event 1/RAW/image6.RAW Removed 2016 spaces/05/event 2/RAW/image9.RAW

With multiple dirs: 

 ]➬./delete.sh "2016 spaces" 2017 Removed 2016 spaces/05/RAW/image3.RAW Removed 2016 spaces/05/event 1/RAW/image6.RAW Removed 2016 spaces/05/event 2/RAW/image9.RAW Removed 2017/05/RAW/image3.RAW Removed 2017/05/event 1/RAW/image6.RAW Removed 2017/05/event 2/RAW/image9.RAW

You can feel free to test it using other solutions commenting out the deleteRAW call in the last line. 

for dir; do createTest "$dir" #deleteRAW "$dir" done

Cheers and best luck. :)

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If correspondence based on the same names but different extention

find 2016 -name '*.RAW' -exec bash -c '[ ! -f "${0//RAW/}jpg" ]' {} \; -delete
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  • @Wildcard I insist for "${0//RAW/}jpg" to remove two entries of RAW in path: compare 2016/05/event1/image4.jpg and 2016/05/event1/RAW/image4.RAW Commented Jun 20, 2016 at 15:17
  • @Gilles Due to above noted variable substitution you can't use sh instead bash Commented Jun 20, 2016 at 15:19
  • Indeed. The version I edited doesn't need bash, but the original does. I hadn't noticed that the raw images were in a different directory and so the %.RAW version is incorrect. Commented Jun 20, 2016 at 15:37
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In zsh, you can use the e glob qualifier to filter wildcard matches.

rm **/*.RAW(e\''[[ ! -e ${REPLY//\/RAW\//\/}:r.jpg ]]'\')
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