5
$\begingroup$

As I had much fun with this (thx Chebhou) but gaussian functions are a bit too complex for me, i want my volume scatter cylinder to have simply a smaller cylinder emitting light inside it, from the same object/material. The same size all along, or why not being able to control the fading at one or both sides (why not asking :) )

It has to be done with math nodes, vectors and things like that (what I want to learn)

Something like this but in a single object enter image description here

looks like a light saber :)

Improve this question
$\endgroup$
2
  • $\begingroup$ related: blender.stackexchange.com/a/15711/1853 and blender.stackexchange.com/a/3640/1853 $\endgroup$ Commented Feb 13, 2015 at 17:11
  • $\begingroup$ @cegaton nope, i don't want a compositing or modeling answer, it has to be shader maths. I already did (long ago) a light saber but i want to learn more about math nodes and vectors in materials. I hope this is simple enough for me to understand the why and how. $\endgroup$ Commented Feb 13, 2015 at 17:16

2 Answers 2

Reset to default
2
$\begingroup$

use this circle equation and chose a radius "max R = 0.5" :

enter image description here

Coordinates node group : enter image description here

and for fading on the sides i used a sin function :

enter image description here

render : enter image description here

Improve this answer
$\endgroup$
5
  • 1
    $\begingroup$ seems like what i wanted, checking details :) $\endgroup$ Commented Feb 13, 2015 at 17:28
  • $\begingroup$ the sin doesn't seem to fade the light, it just stops at both ends. $\endgroup$ Commented Feb 13, 2015 at 18:19
  • $\begingroup$ it fades but in short range that it's not clearly visible because that's how a sin wave is, you can replace with other functions $\endgroup$ Commented Feb 13, 2015 at 18:26
  • 1
    $\begingroup$ Max R=0.5 :) A max value of 1 would be for diameter. $\endgroup$ Commented Feb 15, 2015 at 12:54
  • $\begingroup$ yeah, you are right $\endgroup$ Commented Feb 15, 2015 at 13:23
2
$\begingroup$

Variation on Chebhou's answer : Origin and dimension independant :
enter image description here

Not sure the sine works exactly the same.

Improve this answer
$\endgroup$
1
  • $\begingroup$ that's brilliant ! it is dimension ,and origin dependent $\endgroup$ Commented Feb 15, 2015 at 16:26

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.