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I want to process an asset library that contains four assets, one for each season per Blend file. I want to change the material properties for all objects in the Blend file based on the material name.

I have four objects in the scene, which have a suffix per season: enter image description here

Now I want to change the material properties based on the season and the material itself, the name of which is the text after the last underscore (e.g. "trunk" or "rock").

Ideally, I want to input a list that contains the materials that should be processed, e.g. (leaf_flowers, leaf). Then, I need to change these properties in the main nodegroup: enter image description here

As you can see, input 2 corresponds to the AUTUMN property, input 3 to WINTER and input [4] to SPRING.

The changes are as follows: If the asset contains "_summer", skip it. Summer assets have all 3 properties set by 0 as default. If the asset contains "_autumn" set input 2 to value 1. If the asset contains "_winter" set input 3 to value 1. If the asset contains "_spring" set input [4] to value 1.

Note that a typical material looks something like this: enter image description here So it has one node group and this nodegroup is the one that should be affected.

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Probably something like this will work:

import bpy from bpy import data as D def find_node_by_inputs(nodes, inputs): return next(n for n in nodes if inputs.issubset({i.name for i in n.inputs})) for mat in D.materials: name_parts = mat.name.split('_') if len(name_parts) != 5: # expecting a different name continue season = name_parts[-2].upper() if season == 'SUMMER': continue nodes = mat.node_tree.nodes node = find_node_by_inputs(nodes, {'SPRING', 'AUTUMN'}) # assuming no other node has such two inputs node.inputs[season].default_value = 1

v2

I didn't test this code but it probably works. It has a more aggressive heuristic, matching a material and choosing the season if the word is present in the name, regardless of the punctuation:

import bpy from bpy import data as D seasons = {'SPRING', 'AUTUMN', 'WINTER'} def find_node_by_inputs(nodes, inputs): return next((n for n in nodes if inputs.issubset({i.name for i in n.inputs})), None) for mat in D.materials: detected_season = None name_upper = mat.name.upper() for season in seasons: if season in name_upper: detected_season = season break else: continue nodes = mat.node_tree.nodes node = find_node_by_inputs(nodes, seasons) if node: node.inputs[detected_season].default_value = 1
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  • $\begingroup$ Thanks! As for your assumption in the comments, there is only one node group that has multiple input nodes. It has "VEGETATION_" as name. $\endgroup$ Commented May 31, 2022 at 9:43
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    $\begingroup$ @Hologram then it seems you can replace node = find_node_by_inputs(nodes, {'SPRING', 'AUTUMN'}) with node = nodes['Group'] or node = nodes['VEGETATION_'] if I understood you correctly in regards to the name. $\endgroup$ Commented May 31, 2022 at 10:09
  • $\begingroup$ The node name depends on the material, so it's VEGETATION_[Something else], should have mentioned it's like that. I have added the image in the initial question. ;) Similar nodes also appear in other materials, but not in the same material slot so to say. $\endgroup$ Commented May 31, 2022 at 11:23
  • $\begingroup$ Unfortunately, it doesn't change the properties of the material on my end. I also think there needs to be a debugging. You've used the season as being the part of the name with index -2. There are materials with an additional part with underscore. So sometimes the season is index -3, for instance "summer_leaf_small". I think what should happen is that the underscores after summer should be a dash, so that it becomes "[asset name]_summer_leaf-small". with [asset name] = The name of the asset. $\endgroup$ Commented May 31, 2022 at 11:37
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    $\begingroup$ Thanks! This is awsome! Really cool that you can do so much with Python :) Thanks for all your help Markus! $\endgroup$ Commented Jun 2, 2022 at 9:02

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