0
$\begingroup$

If I am working with the ARMA(1,3) model $$Y_t=Y_{t-1} + \epsilon_t + 0.9\epsilon_{t-3}$$ Where Y's are the observations and $\epsilon$ is a white noise process. I can decompose and find the lag polynomial of the AR part $A(L) = (1-L)$ which means that A(L) has a unit root and therefore is NOT stationary. If I difference the equation using $\Delta(Y_t) = Y_t - T_{t-1}$ to get $$\Delta(Y_t) = \epsilon_t + 0.9\epsilon_{t-3}$$ Im not sure why this process is now stationary? Is it because there is no lag polynomial to have a unit root? Are all AR processess with no lags in $Y_t$ stationary? Is it the case that if the whole lag polynomial is equal to 1 then we have stationarity? Thanks in advance for any help offered.

$\endgroup$

1 Answer 1

0
$\begingroup$

I have found the answer to my own question :@ If the lag polynomial A(L)=1 Then we have stationarity in the ARMA model. Hope this helps someone else in the future!

$\endgroup$

You must log in to answer this question.

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.