The following ODE describes a certain air spring system, which consists of a box with initial volume, and it has a cylinder on its side. By moving the piston in the cylinder we can change the pressure in the box. I would like to study what does happen when we push the piston into the box (making bigger pressure), then we release the piston, so I assume it starts to oscillate. The parameters:
$$A: cylinder's area\\ V_0: initial\ box\ volume\\ p_0: initial\ pressure\\ x(t): the\ position\ of~ the~ cylinder\\ m: mass\ of\ moving\ part$$
Then I made the following equations:
$$p(t)=\frac{V_0p_0}{V_0+Ax(t)}-p_0\\ F(t)=m\cdot a(t)=p(t)\cdot A\\ a(t)=x(t)''=\frac{A\ p(t)}{m}\\$$
From these I have got the following second order non-linear differential equation: $$x(t)''=\frac{V_0\ p_0}{m}\cdot \frac{1}{x(t)+\frac{V_0}{A}}-\frac{A\ p_0}{m}$$ with replaced constants: $$x(t)''=\frac{a}{x(t)+b}-c$$ Then I tried to solve this equation by replacing $$x(t)''=u(x)\cdot u(x)'$$ Finally I have got this equation which I do not understand how to solve: $$x(t)=\int_0^t\sqrt{2\ a\ log(b+x(t))-2\ c\ x}$$