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b = RandomVariate[NormalDistribution[0, 1]]; ListlinePlot[b, PlotRange -> 35]

I am so new to Mathematica. I am trying to generate a 2-dimensional walk with variance =1 and plot this. However, I do not get its plot.

Can you help me? Thank you so much.

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FoldList[Plus, {0, 0}, RandomVariate[NormalDistribution[0, 1], {500, 2}]] // Line // Graphics
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Generate a list of random numbers and Accumulate:

b = Accumulate @ RandomVariate[NormalDistribution[0, 1], 500]; ListLinePlot[b, PlotRange -> 35]

enter image description here

For 2D, you can generate pairs of random numbers and Accumulate:

SeedRandom[1] b2 = Accumulate @ RandomVariate[NormalDistribution[0, 1], {500, 2}]; ListLinePlot[b2, AspectRatio -> Automatic]

enter image description here

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    $\begingroup$ Why do we need {500,2}? Thank you so much! $\endgroup$ Commented Jan 26, 2021 at 1:03
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    $\begingroup$ @Bora, RandomVariate[NormalDistribution[0, 1], {n, m}] generates an nXm matrix the entries of which are independent realizations of a random variable distributed NormalDistribution[0, 1]. $\endgroup$ Commented Jan 26, 2021 at 1:10
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    $\begingroup$ One last question. Is there any way to start the random walk at the origin? I am really grateful for your help. $\endgroup$ Commented Jan 26, 2021 at 1:49
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    $\begingroup$ Prepend the list with {0,0} before accumulating: b2 = Accumulate @ Prepend[RandomVariate[NormalDistribution[0, 1], {500, 2}], {0,0}] $\endgroup$ Commented Jan 26, 2021 at 2:15
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    $\begingroup$ Assuming that the x and y axes are equivalent, it's probably worth using the AspectRatio -> Automatic option on ListLinePlot. $\endgroup$ Commented Jan 26, 2021 at 18:57

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