375

Could someone provide me with a good way of importing a whole directory of modules?
I have a structure like this:

/Foo bar.py spam.py eggs.py 

I tried just converting it to a package by adding __init__.py and doing from Foo import * but it didn't work the way I had hoped.

4
  • 14
    Can you define "didn't work"? What happened? What error message did you get? Commented Jun 29, 2009 at 10:07
  • 1
    Is this Pythonic or recommended? "Explicit is better than implicit." Commented Oct 1, 2016 at 5:28
  • 4
    Explicit is indeed better. But would you really like to address these annoying 'not found' messages everytime you add a new module. I think that if you have a package directory containing many small module-functions, then this is the nicest way to go about it. My assumptions are: 1. module are rather simple 2. you use the package for code tidiness Commented Dec 5, 2019 at 9:23
  • 1
    Note that most (all?) answers on this page will not give you autocomplete in some IDEs and give errors in some linters (they won't "know" what the module is exporting since they don't execute the code). If you're writing a public package and want good 'developer experience', I believe manually declaring what you export is the only way. Commented Aug 10, 2022 at 2:07

24 Answers 24

501

List all python (.py) files in the current folder and put them as __all__ variable in __init__.py

from os.path import dirname, basename, isfile, join import glob modules = glob.glob(join(dirname(__file__), "*.py")) __all__ = [ basename(f)[:-3] for f in modules if isfile(f) and not f.endswith('__init__.py')] 
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14 Comments

Basically so I can drop python files into a directory with no further configuration and have them be executed by a script running somewhere else.
@NiallDouglas this answer is for a specific question which OP asked, he didn't have a zip file and pyc files can be included easily, and you are forgetting .pyd or .so libs etc too
The only thing i would add is if not os.path.basename(f).startswith('_') or at the very least if not f.endswith('__init__.py') to the end of the list comprehension
To make it more robust, also make sure os.path.isfile(f) is True. That would filter out broken symlinks and directories like somedir.py/ (corner-case, I admit, but still...)
Add from . import * after setting __all__ if you want submodules to be available using . (e.g. as module.submodule1, module.submodule2, etc.).
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160

Add the __all__ Variable to __init__.py containing:

__all__ = ["bar", "spam", "eggs"] 

See also http://docs.python.org/tutorial/modules.html

5 Comments

Yes, yes, but is there any way of having it be dynamic?
Combination of os.listdir(), some filtering, stripping of .py extension and __all__.
Not working for me as sample code here github.com/namgivu/python-import-all/blob/master/error_app.py . Maybe I miss something there?
I found out myself - to use the variable/object defined in those modules, we have to use the full reference path e.g. moduleName.varName ref. stackoverflow.com/a/710603/248616
@NamGVU: This code in my answer to a related question will import all the public sub-modules' names into the the package's namespace.
81

Update in 2017: you probably want to use importlib instead.

Make the Foo directory a package by adding an __init__.py. In that __init__.py add:

import bar import eggs import spam 

Since you want it dynamic (which may or may not be a good idea), list all py-files with list dir and import them with something like this:

import os for module in os.listdir(os.path.dirname(__file__)): if module == '__init__.py' or module[-3:] != '.py': continue __import__(module[:-3], locals(), globals()) del module 

Then, from your code do this:

import Foo 

You can now access the modules with

Foo.bar Foo.eggs Foo.spam 

etc. from Foo import * is not a good idea for several reasons, including name clashes and making it hard to analyze the code.

14 Comments

Not bad, but don't forget that you can import .pyc and .pyo files too.
tbh, i find __import__ hackish, i think it would be better to add the names to __all__ and then put from . import * at the bottom of the script
I think this is nicer than the glob version.
__import__ is not for general uses, it used by interpreter, use importlib.import_module() instead.
The first example was very helpful, thanks! Under Python 3.6.4 I had to do from . import eggs etc. in the __init__.py before Python could import. With only import eggs I get ModuleNotFoundError: No module named 'eggs' when trying to import Foo in the main.py in the directory above.
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60

Python, include all files under a directory:

For newbies who just can't get it to work who need their hands held.

  1. Make a folder /home/el/foo and make a file main.py under /home/el/foo Put this code in there:

    from hellokitty import * spam.spamfunc() ham.hamfunc() 
  2. Make a directory /home/el/foo/hellokitty

  3. Make a file __init__.py under /home/el/foo/hellokitty and put this code in there:

    __all__ = ["spam", "ham"] 
  4. Make two python files: spam.py and ham.py under /home/el/foo/hellokitty

  5. Define a function inside spam.py:

    def spamfunc(): print("Spammity spam") 
  6. Define a function inside ham.py:

    def hamfunc(): print("Upgrade from baloney") 
  7. Run it:

    el@apollo:/home/el/foo$ python main.py spammity spam Upgrade from baloney 

3 Comments

Not just for newbies, but also experienced Python devs who like clear answers. Thanks.
But using import * is considered bad Python coding practice. How do you do this without that?
@RachaelBlake I think it's considered bad practice in cases where you're importing all the functions from one namespace into the global namespace. Because you could have overlaps there. In this situation, notice that the namespace of the imported filenames is required (I.E., spam.spamfunc(),). spamfunc and hamfunc aren't in the global namespace, so there's no potential for overlap.
48

Expanding on Mihail's answer, I believe the non-hackish way (as in, not handling the file paths directly) is the following:

  1. create an empty __init__.py file under Foo/
  2. Execute
import pkgutil import sys def load_all_modules_from_dir(dirname): for importer, package_name, _ in pkgutil.iter_modules([dirname]): full_package_name = '%s.%s' % (dirname, package_name) if full_package_name not in sys.modules: module = importer.find_module(package_name ).load_module(full_package_name) print module load_all_modules_from_dir('Foo') 

You'll get:

<module 'Foo.bar' from '/home/.../Foo/bar.pyc'> <module 'Foo.spam' from '/home/.../Foo/spam.pyc'> 

5 Comments

This is most of the way there to a correct answer - it handles ZIP archives, but doesn't write init nor import. See automodinit below.
Another thing: the above example doesn't check sys.modules to see if the module is already loaded. Without that check the above will load the module a second time :)
When I run load_all_modules_from_dir('Foo/bar') with your code I get "RuntimeWarning: Parent module 'Foo/bar' not found while handling absolute import" - to suppress this, I have to set full_package_name = '.'.join(dirname.split(os.path.sep) + package_name]) and also import Foo.bar
Those RuntimeWarning messages can also be avoided by not using full_package_name at all: importer.find_module(package_name).load_module(package_name).
The RuntimeWarning errors can also be avoided (in an arguably ugly way) by importing the parent (AKA dirname). One way to do that is - if dirname not in sys.modules: pkgutil.find_loader(dirname).load_module(dirname). Of course, that only works if dirname is a single-component relative path; no slashes. Personally, I prefer @Artfunkel's approach of using the base package_name instead.
20

I know I'm updating a quite old post, and I tried using automodinit, but found out it's setup process is broken for python3. So, based on Luca's answer, I came up with a simpler answer - which might not work with .zip - to this issue, so I figured I should share it here:

within the __init__.py module from yourpackage:

#!/usr/bin/env python import os, pkgutil __all__ = list(module for _, module, _ in pkgutil.iter_modules([os.path.dirname(__file__)])) 

and within another package below yourpackage:

from yourpackage import * 

Then you'll have all the modules that are placed within the package loaded, and if you write a new module, it'll be automagically imported as well. Of course, use that kind of things with care, with great powers comes great responsibilities.

Comments

16

I got tired of this problem myself, so I wrote a package called automodinit to fix it. You can get it from http://pypi.python.org/pypi/automodinit/.

Usage is like this:

  1. Include the automodinit package into your setup.py dependencies.
  2. Replace all __init__.py files like this:
 __all__ = ["I will get rewritten"] # Don't modify the line above, or this line! import automodinit automodinit.automodinit(__name__, __file__, globals()) del automodinit # Anything else you want can go after here, it won't get modified. 

That's it! From now on importing a module will set __all__ to a list of .py[co] files in the module and will also import each of those files as though you had typed:

for x in __all__: import x 

Therefore the effect of "from M import *" matches exactly "import M".

automodinit is happy running from inside ZIP archives and is therefore ZIP safe.

Niall

2 Comments

pip can't download automodinit because there's nothing uploaded on pypi for it.
Thanks for the bug report on github. I've fixed this in v0.13. Niall
10
import pkgutil __path__ = pkgutil.extend_path(__path__, __name__) for imp, module, ispackage in pkgutil.walk_packages(path=__path__, prefix=__name__+'.'): __import__(module) 

Comments

10

When from . import * isn't good enough, this is an improvement over the answer by ted. Specifically, the use of __all__ is not necessary with this approach.

"""Import all modules that exist in the current directory.""" # Ref https://stackoverflow.com/a/60861023/ from importlib import import_module from pathlib import Path for f in Path(__file__).parent.glob("*.py"): module_name = f.stem if (not module_name.startswith("_")) and (module_name not in globals()): import_module(f".{module_name}", __package__) del f, module_name del import_module, Path 

Note that module_name not in globals() is intended to avoid reimporting the module if it's already imported, as this can risk cyclic imports.

2 Comments

Is the line line really needed if this is encapsulated in a function?
@shay__ The del lines are not needed if the snippet is in a function.
9

I have also encountered this problem and this was my solution:

import os def loadImports(path): files = os.listdir(path) imps = [] for i in range(len(files)): name = files[i].split('.') if len(name) > 1: if name[1] == 'py' and name[0] != '__init__': name = name[0] imps.append(name) file = open(path+'__init__.py','w') toWrite = '__all__ = '+str(imps) file.write(toWrite) file.close() 

This function creates a file (in the provided folder) named __init__.py, which contains an __all__ variable that holds every module in the folder.

For example, I have a folder named Test which contains:

Foo.py Bar.py 

So in the script I want the modules to be imported into I will write:

loadImports('Test/') from Test import * 

This will import everything from Test and the __init__.py file in Test will now contain:

__all__ = ['Foo','Bar'] 

Comments

5

This is the best way i've found so far:

from os.path import dirname, join, isdir, abspath, basename from glob import glob pwd = dirname(__file__) for x in glob(join(pwd, '*.py')): if not x.startswith('__'): __import__(basename(x)[:-3], globals(), locals()) 

1 Comment

abspath and isdir is unused ;)
5

Anurag Uniyal answer with suggested improvements!

#!/usr/bin/python # -*- encoding: utf-8 -*- import os import glob all_list = list() for f in glob.glob(os.path.dirname(__file__)+"/*.py"): if os.path.isfile(f) and not os.path.basename(f).startswith('_'): all_list.append(os.path.basename(f)[:-3]) __all__ = all_list 

Comments

5

Using importlib the only thing you've got to add is

from importlib import import_module from pathlib import Path __all__ = [ import_module(f".{f.stem}", __package__) for f in Path(__file__).parent.glob("*.py") if "__" not in f.stem ] del import_module, Path 

1 Comment

This leads to a legitimate mypy issue: error: Type of __all__ must be "Sequence[str]", not "List[Module]". Defining __all__ is not required if this import_module based approach is used.
5

I'd like to add to Anurag Uniyal's answer. You can make it even simpler and get rid of a lot of the imports. Contents of the __init__.py file:

from os import listdir from os.path import dirname __all__ = [i[:-3] for i in listdir(dirname(__file__)) if not i.startswith('__') and i.endswith('.py')] 

Comments

4

I've created a module for that, which doesn't rely on __init__.py (or any other auxiliary file) and makes me type only the following two lines:

import importdir importdir.do("Foo", globals()) 

Feel free to re-use or contribute: http://gitlab.com/aurelien-lourot/importdir

Comments

4

Anurag's example with a couple of corrections:

import os, glob modules = glob.glob(os.path.join(os.path.dirname(__file__), "*.py")) __all__ = [os.path.basename(f)[:-3] for f in modules if not f.endswith("__init__.py")] 

Comments

3

See that your __init__.py defines __all__. The modules - packages doc says

The __init__.py files are required to make Python treat the directories as containing packages; this is done to prevent directories with a common name, such as string, from unintentionally hiding valid modules that occur later on the module search path. In the simplest case, __init__.py can just be an empty file, but it can also execute initialization code for the package or set the __all__ variable, described later.

...

The only solution is for the package author to provide an explicit index of the package. The import statement uses the following convention: if a package’s __init__.py code defines a list named __all__, it is taken to be the list of module names that should be imported when from package import * is encountered. It is up to the package author to keep this list up-to-date when a new version of the package is released. Package authors may also decide not to support it, if they don’t see a use for importing * from their package. For example, the file sounds/effects/__init__.py could contain the following code:

__all__ = ["echo", "surround", "reverse"]

This would mean that from sound.effects import * would import the three named submodules of the sound package.

Comments

2

None of the solutions was working for me in Python 3.9.5, Flask 2.2.2, the module being a directory 2 levels down the cwd. This is my solution:

import importlib import pathlib import re path = pathlib.Path(__file__).parent.absolute() names = [x.name[:-3] for x in path.iterdir() if x.is_file() and re.search("^[a-z]*\.py$", x.name)] for name in names: importlib.import_module(f".{name}", __name__) 

Comments

1

Look at the pkgutil module from the standard library. It will let you do exactly what you want as long as you have an __init__.py file in the directory. The __init__.py file can be empty.

Comments

1

Just import them by importlib and add them to __all__ (add action is optional) in recurse in the __init__.py of package.

/Foo bar.py spam.py eggs.py __init__.py # __init__.py import os import importlib pyfile_extes = ['py', ] __all__ = [importlib.import_module('.%s' % filename, __package__) for filename in [os.path.splitext(i)[0] for i in os.listdir(os.path.dirname(__file__)) if os.path.splitext(i)[1] in pyfile_extes] if not filename.startswith('__')] del os, importlib, pyfile_extes 

2 Comments

Where is pyfile_extes defined?
sorry for missing it, now fixed. It is the extention of python file you want to import, usually just py
1

Here is a solution, with which you do not have to write the file name. Just add this code snippet to your __init__.py

from inspect import isclass from pkgutil import iter_modules from pathlib import Path from importlib import import_module # iterate through the modules in the current package package_dir = Path(__file__).resolve().parent for (_, module_name, _) in iter_modules([package_dir]): # import the module and iterate through its attributes module = import_module(f"{__name__}.{module_name}") for attribute_name in dir(module): attribute = getattr(module, attribute_name) if isclass(attribute): # Add the class to this package's variables globals()[attribute_name] = attribute 

Source

Comments

0

I had a nested directory structure i.e. I had multiple directories inside the main directory that contained the python modules.

I added the following script to my __init__.py file to import all the modules

import glob, re, os module_parent_directory = "path/to/the/directory/containing/__init__.py/file" owd = os.getcwd() if not owd.endswith(module_parent_directory): os.chdir(module_parent_directory) module_paths = glob.glob("**/*.py", recursive = True) for module_path in module_paths: if not re.match( ".*__init__.py$", module_path): import_path = module_path[:-3] import_path = import_path.replace("/", ".") exec(f"from .{import_path} import *") os.chdir(owd) 

Probably not the best way to achieve this, but I couldn't make anything else work for me.

Comments

0

If you want use import all with pyinstaller, you'll need the following extra processing.

  1. define get_all_pyfile that support .pyc

util/get_all_pyfile

import glob import re from os.path import join, basename, isfile from typing import AnyStr def get_all_pyfile(pathname: AnyStr): modules = glob.glob(join(pathname, "*.py*")) return [ re.sub(r"\.pyc?", "", basename(f)) for f in modules if isfile(f) and not re.search(r"__init__.pyc?$", f) ] 
  1. use get_all_pyfile in __init__.py

entity/__init__.py

from os.path import dirname from util.get_all_pyfile import get_all_pyfile __all__ = get_all_pyfile(dirname(__file__)) 
  1. add hidden imports in pyinstaller spec file

/main.spec

# -*- mode: python ; coding: utf-8 -*- import os import sys from PyInstaller.building.api import PYZ, EXE, COLLECT from PyInstaller.building.build_main import Analysis from PyInstaller.utils.hooks import collect_submodules venv_path = os.path.dirname(os.path.realpath("__file__")) sys.path.append(os.path.join(venv_path, "../")) hidden_imports_entity = collect_submodules("entity") print(hidden_imports_entity) a = Analysis( [".\\main.py"], pathex=[], binaries=[], datas=[], hiddenimports=hidden_imports_entity, hookspath=[], hooksconfig={}, runtime_hooks=[], excludes=[], noarchive=True, ) ... 

Comments

0

This isn't the same thing exactly, but is a potentially related solution.

If you're importing for future utilization (instead of importing for side-effects), you can use PEP562 to automatically import on use:

def __getattr__(name): import importlib return importlib.import_module(f".{name}", __name__) 

This might be useful for plugins or web frameworks where you need to pull a consistent object out of a pile of submodules.

Comments

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