python add character to filename

Question

Im trying to add a "." after the last occurrence of a integer starting backwards from ".html"

python

import os import glob import re for name in glob.glob('*.html'): newname = re.compile('name(.*?)(\d+)') os.rename(name, newname)

change filenames from:

1cor12.html gen1.html

to:

1cor.12.html gen.1.html

mfussenegger · Accepted Answer · 2012-05-21 19:12:27Z

3

Something like should do:

re.sub('(\d+)(?=\.html)', r'.\1', s)

answered May 21, 2012 at 19:12

mfussenegger

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1 Comment

kojiro Over a year ago

This also does not work if the digits don't immediately follow the .html.

mgilson · Accepted Answer · 2012-05-21 19:24:36Z

2

Is this what you want?

re.sub(r'(\d+\.html)',r'.\1',r'1cor12.html')

Note, this only works if you want numbers immediately preceding ".html". In other words, this will do nothing to "gen1a.html".

If you want to match the latter case ('gen1a.html') you could probably do something like:

re.sub(r'(\d+\D*\.html)',r'.\1',r'1cor12.html')

edited May 21, 2012 at 19:24

answered May 21, 2012 at 19:04

mgilson

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5 Comments

kojiro Over a year ago

That won't work if the digits don't immediately precede the .html.

Blainer Over a year ago

the digits always come before .html but did not change "gen1.html" to "gen.1.html"

mgilson Over a year ago

@kojiro -- Yeah, I know. I was assuming the problem was a little easier than stated (hence the "is this what you what?"), but I suppose I'll document that.

mgilson Over a year ago

@kojiro -- Fixed so it will work if digits don't immediately precede the .html

kojiro Over a year ago

@mgilson nicely done. It even matches 1a2b3c.html, returning 1a2b.3c.html, which is exactly what OP asked for. Too bad he didn't ask for what he actually wanted.

Joel Cornett · Accepted Answer · 2012-05-21 21:00:03Z

0

newname = "%s.%s.html" % re.match(r"(.*)(\d+)\.html", oldname).groups()

answered May 21, 2012 at 21:00

Joel Cornett

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