I am creating files dynamically in different folders, like so:
curr_dir = "/a/b/c" filename = os.path.join(curr_dir, 'file.text') Which gives me:
"/a/b/c/file.text" But because I am creating files with the same name in many folders, I want to distinguish them by adding the folder's name as a prefix, to get:
"a/b/c/c_file.text" How can I get that?
Try the pathlib package instead:
>>> from pathlib import Path >>> Path() WindowsPath('.') >>> Path().absolute() WindowsPath('C:/Users/p00200284/test') >>> Path().absolute().parent WindowsPath('C:/Users/p00200284') >>> Path().absolute().parent / "all_files.tex" WindowsPath('C:/Users/p00200284/all_files.tex') >>> str(Path().absolute().parent / "all_files.tex") 'C:\\Users\\p00200284\\all_files.tex' >>> Path().absolute().parent.name 'p00200284' >>> f"{Path().absolute().parent.name}_all_files.tex" 'p00200284_all_files.tex' >>> parent_dir = Path().absolute().parent >>> parent_dir / f"{Path().absolute().parent.name}_all_files.tex" WindowsPath('C:/Users/p00200284/p00200284_all_files.tex') 
texfile = os.path.join(curr_dir, 'all_files.tex') only concatenates the current directory path to your filename.
You should have something like:
texfile = os.path.join(curr_dir, os.path.basename(curr_dir)+'_all_files.tex') 
