How do I dynamically bind a socket to only one network interface?

Question

Currently I do the following to listen on any available port on all interfaces:

// hints struct for the getaddrinfo call struct addrinfo hints, *res; memset(&hints, 0, sizeof hints); hints.ai_family = AF_INET; hints.ai_socktype = SOCK_STREAM; hints.ai_flags = AI_PASSIVE; // Fill in addrinfo with getaddrinfo if (getaddrinfo(NULL, "0", &hints, &res) != 0) { cerr << "Couldn't getaddrinfo." << endl; exit(-1); }

I would like to dynamically bind to only one interface, the non-loopback interface of the system.

How would I go about doing this?

Brian Agnew · Accepted Answer · 2009-07-13 13:25:54Z

5

Take a look at SO_BINDTODEVICE. Tuxology has a good description of this

answered Jul 13, 2009 at 13:25

Brian Agnew

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Henk Poley Over a year ago

Site is down, cached copy here: web.archive.org/web/20090812134009/http://tuxology.net/tag/…

hoohoo · Accepted Answer · 2009-07-13 15:15:44Z

If you want an excellent book on the matter:

UNIX Network Programming by W. Richard Stevens, in two volumes. Volume one covers sockets.

Also Advanced Programming in the UNIX Environment, also by Stevens and updated in 3rd edition by Rago.

These are widely considered to be classics and standard references for UNIX / Linux / et al

Beano · Accepted Answer · 2009-07-13 15:21:15Z

1

You can use the SIOCGIFADDR ioctl() to determine the IP address of a specific interface, and then bind() to that address.

answered Jul 13, 2009 at 15:21

Beano

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1 Comment

ephemient Over a year ago

This is most common solution, though it breaks down if you have multiple interfaces with the same address or your interfaces change addresses.

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