PHP5 Using a class within a class

Question

I am trying to use a class within a class, but seem to be having an issue with the initialised content of the class. It can see the class structure fine if you do a var_dump, but it wont see the content you have initialised with. I know im probably missing something pretty obvious, any pointers would be great. An example is below...

class firstClass() { public $thedate; function __construct() { $this->thedate = date(); } } class secondClass() { public $datefrom1stclass; function __construct() { $this->datefrom1stclass = new firstClass; echo $this->datefrom1stclass->thedate; } }

Sorry if I have not explained very well, If I do a var_dump I get the following:

object(firstClass)#3 (1) { ["thedate"]=> NULL }

Any pointers would be appreciated!

Once you fix the syntax errors and pass an argument to date(), it works fine: codepad.org/kDvuEWR3 — deceze
– deceze ♦, Commented Jul 9, 2012 at 11:06
Sorry guys, looks like I missed an 'S' out of __construct for the first class, which is why it wasnt being initialised with anything!! — Dan
– Dan, Commented Jul 9, 2012 at 11:16

raina77ow · Accepted Answer · 2012-07-09 11:08:32Z

You shouldn't call date() without any parameters: at least one (a format, as a string) should be given:

$this->thedate = date('D M j G:i:s T Y');

The rest of your code is correct (although I'd prefer new firstClass() form, with parentheses - it's more readable).

Amit Sharma · Accepted Answer · 2012-07-09 11:26:30Z

Here is the correct code :) Enjoy `

public $thedate; function __construct() { $this->thedate = date("Ymd"); }

}

class secondClass {

public $datefrom1stclass; function __construct() { $this->datefrom1stclass = new firstClass; echo $this->datefrom1stclass->thedate; }

} $var = new secondClass(); var_dump( $var ); ?> `

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