django template: get dictionary value

Question

My view function does the following:

search_parameters = {"words": "hello"} return render('mypage.html', {'results': results, 'search_parameters':search_parameters})

In my template, I thought I could get "hello" by writing:

{{search_parameters.words}}

but it's blank.

What does work is looping through every value like so

{% for key,value in search_parameters.items %}

but I'd really like to avoid doing that every time I need to get a value from the dictionary.

{{search_parameters.words}} would work. There's something else wrong. — Daniel Roseman
– Daniel Roseman, Commented Oct 21, 2012 at 19:51
Are you using render correctly? According to docs (docs.djangoproject.com/en/dev/topics/http/shortcuts/#render), the first required parameter is request which you do not pass. Maybe you meant to use render_to_response? — miki725
– miki725, Commented Oct 21, 2012 at 19:54
{{search_parameters.words}} did magically work once my computer and I had a good nights sleep. (I actually used render_to_response, not render) — user984003
– user984003, Commented Oct 31, 2012 at 10:06

Asi · Accepted Answer · 2013-11-25 23:43:45Z

Like miki725 have pointed out, you're missing the request arg

search_parameters = {"words": "hello"} return render( request, 'mypage.html', {'results': results, 'search_parameters':search_parameters} )

then you could do {{ search_parameters.words }} as you wish

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