How do I subtract a word from the output in bash

Question

I made a simple bash script to convert movies from .avi to .mp4 but now I want to do two more things.

Have the output file have only *.mp4 rather than *.avi.mp4
Delete the old file after the conversion is completed.

Here is my script.

#!/bin/bash avconv -i "$1" -c:v libx264 -c:a copy -sn -crf 24 "$1".mp4

Janito Vaqueiro Ferreira Filho · Accepted Answer · 2012-10-23 15:53:47Z

You should do ${1%.avi}.mp4, where we tell bash to print the contents of $1 with the .avi suffix removed, and then append the .mp4 suffix.
I would suggest running aconv ... && rm "$1", in order to only delete if conversion succeeds, because the && operator only executes the command that follows it if the previous command succeeds.

Final version:

#!/bin/bash avconv -i "$1" -c:v libx264 -c:a copy -sn -crf 24 "${1%.avi}.mp4" && rm "$1"

Hope this helps =)

Hai Vu · Accepted Answer · 2012-10-24 14:45:11Z

2

How about:

avconv -i "$1" -c:v libx264 -c:a copy -sn -crf 24 "${1/.avi/.mp4}" && rm "$1"

UPDATE

In response to the comment, the syntax for search and replace is:

${1/oldstring/newstring}

So, you can use it any way you want.

edited Oct 24, 2012 at 14:45

answered Oct 23, 2012 at 15:56

Hai Vu

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1 Comment

Happyworker Over a year ago

Thank you very much. If I had a file that was a *.mkv and I wanted to subtract that, would I then do this? 'avconv -i "$1" -c:v libx264 -c:a copy -sn -crf 24 "${1/.avi/.mkv}.mp4" && rm "$1"'

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