I have if statement
if "1111111" in players or "0000000" in players or "blablabla" in players: do something How to write in short ?
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3 Answers
if any(x in players for x in ("1111111", "0000000", "blablabla")): # do something If you are going to be doing a lot of these membership checks you may consider making players into a set which doesn't need to potentially traverse the entire sequence on each check.
Comments
You can use any():
things = ["1111111", "0000000", "blablabla"] if any(thing in players for thing in things): 
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if any(a in players for a in list_of_tests): #something pass If you are using numpy.any(), you will need to convert the generator to a list first.
if np.any([a in players for a in list_of_tests]): #something pass 
3 Comments
tacaswell
@Blender thanks, wasn't sure when I wrote it if
any played nice with generators. I am used to using numpy.any which I am pretty sure does not.
Blender
I think
numpy.any should work as well. All you're doing is iterating until the first False.tacaswell
@Blender
np.any (on 1.7) will return a generator if you pass it a generator. It makes assumptions about the input being array-like. Probably related to what you get if you do np.array(t for t in src) (which is an array with a single generator element).