Short if statement with or in Python

Question

I have if statement

if "1111111" in players or "0000000" in players or "blablabla" in players: do something

How to write in short ?

jamylak · Accepted Answer · 2013-04-14 07:20:30Z

if any(x in players for x in ("1111111", "0000000", "blablabla")): # do something

If you are going to be doing a lot of these membership checks you may consider making players into a set which doesn't need to potentially traverse the entire sequence on each check.

Blender · Accepted Answer · 2013-04-14 06:51:39Z

You can use any():

things = ["1111111", "0000000", "blablabla"] if any(thing in players for thing in things):

tacaswell · Accepted Answer · 2013-04-14 07:07:52Z

2

if any(a in players for a in list_of_tests): #something pass

If you are using numpy.any(), you will need to convert the generator to a list first.

if np.any([a in players for a in list_of_tests]): #something pass

edited Apr 14, 2013 at 7:07

answered Apr 14, 2013 at 6:51

tacaswell

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3 Comments

tacaswell Over a year ago

@Blender thanks, wasn't sure when I wrote it if any played nice with generators. I am used to using numpy.any which I am pretty sure does not.

Blender Over a year ago

I think numpy.any should work as well. All you're doing is iterating until the first False.

tacaswell Over a year ago

@Blender np.any (on 1.7) will return a generator if you pass it a generator. It makes assumptions about the input being array-like. Probably related to what you get if you do np.array(t for t in src) (which is an array with a single generator element).

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Short if statement with or in Python

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