I tried:
d = {3:'a',2:'b'} if 'B' in d.values(): print 'True' For me B is equal to b, but I don't want change my dictionary.
It is possible test for case insensitive matches against the values of a dictionary?
How to check if 'B' is present in the dictionary without changing the values?
More complex:
d = {3:'A',2:'B',6:'c'} You'd have to loop through the values:
if any('B' == value.upper() for value in d.itervalues()): print 'Yup' For Python 3, replace .itervalues() with .values(). This tests the minimum number of values; no intermediary list is created, and the any() loop terminates the moment a match is found.
Demo:
>>> d = {3:'a',2:'b'} >>> if any('B' == value.upper() for value in d.itervalues()): ... print 'Yup' ... Yup 
if 'b' in map(str.lower, d.values()): ... 
imap and dict.itervalues(), as it returns an iterator.
map already returns an iterator, but in py2.x it'll create a list first and then it'll look for 'b' in it. Related: stackoverflow.com/q/11963711/846892if filter(lambda x:d[x] == 'B', d): print "B is present else: print "b is not present" Try this ..
import sys d = {3:'A',2:'B',6:'c'} letter = (str(sys.argv[1])).lower() if filter(lambda x : x == letter ,[x.lower() for x in d.itervalues()]): print "%s is present" %(letter) else: print "%s is not present" %(letter) 