Is there are way to pass a method as a parameter without using a Proc object or block? The answers I've seen to similar questions rely on creating a Proc object.
def call_a_method_via_a_parameter( &some_method ) # ?? call some_method and pass it a parameter ?? end def my_method( param ) puts param end call_a_method_via_a_parameter( &:my_method ) 
def bob(jeff) puts "hi #{jeff}" end def mary(meth, params) meth.call(params) end mary(method(:bob), 'yo') => hi yo Ruby is an object-oriented language. You can only pass around and manipulate objects, but methods aren't objects, ergo, you cannot pass them around.
You can, however, ask Ruby to give you a proxy object for a method via the Object#method method, which will return a Method object (which duck-types Proc):
def call_a_method_via_a_parameter(some_method) some_method.('Hi') end def my_method(param) puts param end call_a_method_via_a_parameter(method(:my_method)) # Hi An alternative would be to pass the name of the method as a Symbol:
def call_a_method_via_a_parameter(some_method) public_send(:some_method, 'Hi') end def my_method(param) puts param end call_a_method_via_a_parameter(:my_method) # Hi So, in short: no, you cannot pass the method, but you can pass either the name of the method or a proxy object for the method.
However, the idiomatic way would be to use a block:
def call_a_method_via_a_parameter yield 'Hi' end def my_method(param) puts param end call_a_method_via_a_parameter(&method(:my_method)) # Hi 