Java - How to show Soap Fault

Question

I have this kind of response when having a Soap Fault calling a Java Web Service

<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <soap:Fault> <faultcode>soap:Server</faultcode> <faultstring>Fault occurred while processing.</faultstring> <detail> <ns1:WaybillRegistrationFault xmlns:ns1="http://pod.waybillmanagement.ws.industrysystem.com.ar/"> <errors xmlns:ns2="http://pod.waybillmanagement.ws.industrysystem.com.ar/"> <code>80000</code> <description>El número de CTG 20140904 ya existe</description> </errors> <errors xmlns:ns2="http://pod.waybillmanagement.ws.industrysystem.com.ar/"> <code>1000</code> <description>La carta de porte ya se encuentra registrada.</description> </errors> </ns1:WaybillRegistrationFault> </detail> </soap:Fault> </soap:Body> </soap:Envelope>

I did an Soap Handler with its handleFault method like this: public boolean handleFault(SOAPMessageContext context) {

 try { System.err.println("Handler handleFault"); if (context.getMessage().getSOAPBody().hasFault()) { SOAPFault fa = context.getMessage().getSOAPBody().getFault(); System.err.println(fa.getFaultString()); System.err.println("FaultCode: " + fa.getFaultCode() + " - Detail: " + fa.getDetail()); } return true; } catch (SOAPException ex) { System.err.println("SoapEx " + ex.getMessage()); return true; } }

But in my output all I have is :

Handler handleFault Fault occurred while processing. FaultCode: soap:Server - Detail: [detail: null]

How do I process the errors node?

Update:

with fa.getDetail().getFirstChild().getTextContent() I get the text within the xml. How do I get that as an object. It be a WaybillRegistrationFault I think.

Bashir · Accepted Answer · 2020-08-18 11:00:05Z

This is the way that I always handle soap fault errors:

StringWriter sw = new StringWriter(); TransformerFactory.newInstance().newTransformer().transform( new DOMSource(soapFaultException.getFault()), new StreamResult(sw)); String xml = sw.toString();

omer.dogan · Accepted Answer · 2014-09-10 22:28:27Z

if you want to print fault content as a xml string , you must convert the dom instance returned by the fa.getDetail() to String , fa.getDetail().toString() return ["+getNodeName()+": "+getNodeValue()+"]" not the content of the xml.

try the following;

String detailStr=dom2string(fa.getDetail()) System.err.println("FaultCode: " + fa.getFaultCode() + " - Detail: " + detailStr); public static final String dom2string(Node node) { try { if (node == null) { return null; } Transformer tf = transformerThreadLocal.get(); // Create writer StringWriter sw = new StringWriter(buffer, Integer.MAX_VALUE); StreamResult result = new StreamResult(sw); // transform tf.transform(new DOMSource(node), result); return sw.getBuffer(); } catch (Exception e) { throw new RuntimeException("Could not convert Node to string", e); } }

Executing fa.getDetail().getFirstChild().getTextContent() I get the message but all in text format, is there a way to have it as an object?
It's worth noticing that it's not an Java object, but an XML sort of object, which I had to parse through Node and NodeList.
I highly recommend using xmlbeans if you prefer handling xml document as objects instead of dom. Check xmlbeans.apache.org

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