QT Signal / Slot

Question

I've got a question about signals and slots. In my app, I want to connect a signal from one object to a textEdit in a dialog window. My signal emits a QString; if I violate encapsulation (by making the UI public instead of private) and connect the signal directly to the textEdit it works. But I feel that it's not the right way. If I make something like the following:

connect(m_osgWidget->picker.get(), SIGNAL(setX(QString)), m_addAgentDlg, SLOT(getX(QString)));

where:

void getX(QString) { this->ui.textEdit(QString); }

It gives me an error that I can't use QString in this this->ui.textEdit(QString); I need the QString from setX() signal pasted into the textEdit of m_addAgentDlg. How this can be done? Where did I make a mistake?

László Papp · Accepted Answer · 2014-12-06 21:23:04Z

2

I am sorry to say this, but you need to learn basic C++. The proper syntax is this for such things in C++ with Qt:

connect(m_osgWidget->picker.get(), SIGNAL(setX(const QString&)), m_addAgentDlg, SLOT(getX(const QString&))); // Why do you call it getX? Should it be called setText instead? void getX(const QString& string) { ui->textEdit->setText(string); }

answered Dec 6, 2014 at 21:23

László Papp

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2 Comments

Azraith Sherkhan Over a year ago

Well, i still learn so it's not necessary to say. I have tried every possible type of code posted above, including one that you provided. It doesn't work. Thats why i ask it here. I continue get messages that there is no such slot in object.

László Papp Over a year ago

@AzraithSherkhan: you have to rerun qmake, but please buy a C++ book. It is necessary to say as these situations are why the authors spent their lives with them.

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