Haskell (-1) number issue

Question

Imagine this:

f = (*10) . (+1)

It is a simple way to say to add 1 and then multiply by 10. Now check the following:

f = (* 10) . (-1)

Here -1 is a number, not a function, I would like to know if there is a function available to avoid this

\x -> x - 1

or this

flip (-) 1

I know they are right, but I would like to not make it be like that.

The Internet · Accepted Answer · 2016-04-21 02:55:42Z

5

Subtracting numbers can be accomplished via the subtract function

subtract 1 is equivalent to \x -> x - 1

So,

f = (* 10) . subtract 1

answered Apr 21, 2016 at 2:53

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3 Comments

I've found it on hoogle at the same time you answered! I think I am getting tired :P, this is the exactly right function.

Fantastic :) Mark it if you want

I will, I am just waiting the waiting time