Syntax error in len(sys.argv)

Question

Python interpreter gives Syntax error while running below code:

import sys if len(sys.argv) == 3: a=sys.argv[1] b=sys.argv[2] sum=int(a) + int(b) print "The sum is: ", sum elif len(sys.argv) != 3: print "Only two arguments allowed !" else: print "Please enter two numbers as argument with the script. Try again !"

Error:

luckee@zarvis:~/python$ ./sumtwo.py 5 10 ./sumtwo.py: line 3: syntax error near unexpected token `sys.argv' ./sumtwo.py: line 3: `if len(sys.argv) == 3:'

Your file is interpreted by your shell, not Python interpreter. Try python sumtwo.py or adding #!python as a first file of your file. — Łukasz Rogalski
– Łukasz Rogalski, Commented Jun 16, 2016 at 18:44
Rogalski's got it. Also this is somewhat tangential, but your if and elif clauses cover every possibilty - len(sys.argv) has to be either == 3 or != 3. The else will never get triggered. — keys
– keys, Commented Jun 16, 2016 at 18:47

Łukasz Rogalski · Accepted Answer · 2016-06-16 18:46:21Z

Your file is interpreted by your shell, not Python interpreter. Try specifying binary when running it:

luckee@zarvis:~/python$ python sumtwo.py 5 10

Alternatively, you may add shebang as a first line of your script.

#!/usr/bin/python import sys if len(sys.argv) == 3: a=sys.argv[1] b=sys.argv[2] sum=int(a) + int(b) print "The sum is: ", sum elif len(sys.argv) != 3: print "Only two arguments allowed !" else: print "Please enter two numbers as argument with the script. Try again !"

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