I have just found the great solution that works for me.

const getDefaultState = () => { return { items: [], status: 'empty' } } // initial state const state = getDefaultState() const actions = { resetCartState ({ commit }) { commit('resetState') }, addItem ({ state, commit }, item) { /* ... */ } } const mutations = { resetState (state) { // Merge rather than replace so we don't lose observers // https://github.com/vuejs/vuex/issues/1118 Object.assign(state, getDefaultState()) } } export default { state, getters: {}, actions, mutations } 

Thanks to Taha Shashtari for the great solution.

Michael,

Update after using the below solution a bit more

So it turns out that if you use replaceState with an empty object ({}) you end up bricking reactivity since your state props go away. So in essence you have to actually reset every property in state and then use store.replaceState(resetStateObject). For store without modules you'd essentially do something like:

let state = this.$store.state; let newState = {}; Object.keys(state).forEach(key => { newState[key] = null; // or = initialState[key] }); this.$store.replaceState(newState); 

Update (from comments): What if one needs to only reset/define a single module and keep the rest as they were?

If you don't want to reset all your modules, you can just reset the modules you need and leave the other reset in their current state.

For example, say you have mutliple modules and you only want to reset module a to it's initial state, using the method above^, which we'll call resetStateA. Then you would clone the original state (that includes all the modules before resetting).

var currentState = deepClone(this.state) 

where deepClone is your deep cloning method of choice (lodash has a good one). This clone has the current state of A before the reset. So let's overwrite that

var newState = Object.assign(currentState, { a: resetStateA }); 

and use that new state with replaceState, which includes the current state of all you modules, except the module a with its initial state:

this.$store.replaceState(newState); 

Original solution

I found this handy method in Vuex.store. You can clear all state quickly and painlessly by using replaceState, like this:

store.replaceState({}) 

It works with a single store or with modules, and it preserves the reactivity of all your state properties. See the Vuex api doc page, and find in page for replaceState.

For Modules

IF you're replacing a store with modules you'll have to include empty state objects for each module. So, for example, if you have modules a and b, you'd do:

store.replaceState({ a: {}, b: {} }) 

You can declare an initial state and reset it to that state property by property. You can't just do state = initialState or you lose reactivity.

Here's how we do it in the application I'm working on:

let initialState = { "token": null, "user": {} } const state = Vue.util.extend({}, initialState) const mutations = { RESET_STATE(state, payload) { for (let f in state) { Vue.set(state, f, initialState[f]) } } } 

I am not sure what you use case is, but I had to do something similar. When a user logs out, I want to clear the entire state of the app - so I just did window.reload. Maybe not exactly what you asked for, but if this is why you want to clear the store, maybe an alternative.

If you do a state = {}, you will remove the reactivity of the properties and your getters mutations will suddenly stop working.

you can have a sub-property like:

state: { subProperty: { a: '', lot: '', of: '', properties: '', . . . } } 

Doing a state.subProperty = {} should help, without losing the reactivity.

You should not have a state too big, break them down to different modules and import to your vuex store like so:

import Vue from 'vue' import Vuex from 'vuex' import authorization from './modules/authorization' import profile from './modules/profile' Vue.use(Vuex) export const store = new Vuex.Store({ modules: { authorization, profile } }) 

now in your individual files:

// modules/authorization.js import * as NameSpace from '../NameSpace' import { someService } from '../../Services/something' const state = { [NameSpace.AUTH_STATE]: { auth: {}, error: null } } const getters = { [NameSpace.AUTH_GETTER]: state => { return state[NameSpace.AUTH_STATE] } } const mutations = { [NameSpace.AUTH_MUTATION]: (state, payload) => { state[NameSpace.AUTH_STATE] = payload }, } const actions = { [NameSpace.ASYNC_AUTH_ACTION]: ({ commit }, payload) => { someService.login(payload.username, payload.password) .then((user) => { commit(NameSpace.AUTH_MUTATION, {auth: user, error: null}) }) .catch((error) => { commit(NameSpace.AUTH_MUTATION, {auth: [], error: error}) }) } } export default { state, getters, mutations, actions } 

If you should want to clear the state you can just have a mutation implement:

state[NameSpace.AUTH_STATE] = { auth: {}, error: null } 

Here's a solution that works in my app. I created a file named defaultState.js.

//defaultState.js //the return value is the same as that in the state const defaultState = () => { return { items: [], poles: {}, ... } } export default defaultState 

And then Where you want to use it

//anywhere you want to use it //for example in your mutations.js //when you've gotten your store object do import defaultState from '/path/to/defaultState.js' let mutations = { ..., clearStore(state){ Object.assign(state, defaultState()) }, } export default mutations 

Then in your store.js

import Vue from 'vue'; import Vuex from 'vuex'; import actions from './actions'; import getters from './getters'; import mutations from './mutations'; //import mutations import state from './state'; Vue.use(Vuex); export default new Vuex.Store({ actions, mutations, state, getters, }); 

and That's it

If you want to reset your entire state you can use the built in replaceState method.

Given a state set in index.js:

 const state = { user: '', token: '', products: [] /* etc. */ } const initialStateCopy = JSON.parse(JSON.stringify(state)) export const store = new Vuex.Store({ state, /* getters, mutations, etc. */ }) export function resetState() { store.replaceState(initialStateCopy) } 

Then in your vue component (or anywhere) import resetState:

 import { resetState } from '@/store/index.js' // vue component usage, for example: logout { // ... data(), computed etc. omitted for brevity methods: { logout() { resetState() } } } 

Based on these 2 answers (#1 #2) I made a workable code.

My structure of Vuex's index.js:

import Vue from 'vue' import Vuex from 'vuex' import createPersistedState from 'vuex-persistedstate' import { header } from './header' import { media } from './media' Vue.use(Vuex) const store = new Vuex.Store({ plugins: [createPersistedState()], modules: { header, media } }) export default store 

Inside each module we need to move all states into separated var initialState and in mutation define a function resetState, like below for media.js:

const initialState = () => ({ stateOne: 0, stateTwo: { isImportedSelected: false, isImportedIndeterminate: false, isImportedMaximized: false, isImportedSortedAsc: false, items: [], stateN: ... } }) export const media = { namespaced: true, state: initialState, // <<---- Our States getters: { }, actions: { }, mutations: { resetState (state) { const initial = initialState() Object.keys(initial).forEach(key => { state[key] = initial[key] }) }, } } 

In Vue component we can use it like:

<template> </template> <script> import { mapMutations } from 'vuex' export default { name: 'SomeName', data () { return { dataOne: '', dataTwo: 2 } }, computed: { }, methods: { ...mapMutations('media', [ // <<---- define module 'resetState' // <<---- define mutation ]), logout () { this.resetState() // <<---- use mutation // ... any code if you need to do something here } }, mounted () { } } // End of 'default' </script> <style> </style> 

Call router.go() or this.$router.go()

That will refresh the page and your state will be reset to how it was when the user first loaded the app.

Myself has read above and implemented a solution. could help you as well!!

All objects stored in Vue act as an observable. So if reference of a value is changed/mutated it triggers the actual value to be changed too.

So, Inorder to reset the state the initial store modules has to be copied as a value.

On logging out of an user, the same value has to be assigned for each modules as a copy.

This can be achieved as following:

Step 1: Create a copy of your initial module.

// store.ts // Initial store with modules as an object export const initialStoreModules = { user, recruitment, }; export default new Vuex.Store({ /** * Assign the modules to the store * using lodash deepClone to avoid changing the initial store module values */ modules: _.cloneDeep(initialStoreModules), mutations: { // reset default state modules by looping around the initialStoreModules [types.RESET_STATE](state: any) { _.forOwn(initialStoreModules, (value: IModule, key: string) => { state[key] = _.cloneDeep(value.state); }); }, } }); 

Step 2: Call the action to mutate the state to initial state.

// user_action.ts const logout = ({ commit }: any) => { commit(types.LOGOUT_INIT); new UserProxy().logout().then((response: any) => { router.push({ name: 'login', }); // reset the state commit(types.RESET_STATE); }).catch((err: any) => { commit(types.LOGOUT_FAIL, err); }); }; 

You could take it easy by tiny package: vuex-extensions

Check out the example on CodeSandbox.

Creating Vuex.Store

import Vuex from 'vuex' import { createStore } from 'vuex-extensions' export default createStore(Vuex.Store, { plugins: [] modules: {} }) 

// Vue Component this.$store.reset() 

// Vuex action modules: { sub: { actions: { logout() { this.reset() } } } } 

You can do this

index.js

... const store = new Vuex.Store({ modules: { ... } }) store.initialState = clone(store.state) store.resetState = () => { store.replaceState(store.initialState) } export default store 

Other place

this.$store.resetState() 

function initialState () { return { /* .. initial state ... */ } } export default { state: initialState, mutations: { reset (state) { // acquire initial state const s = initialState() Object.keys(s).forEach(key => { state[key] = s[key] }) } } } 

This is an official recommendation issue

if you clear your complete vuex store use:

sessionStorage.clear(); 

My way to reset named modules.

I create a dynamic vuex module on beforeCreate() hook in the layout.vue. (ES6 only)

// default.vue beforeCreate() { this.$store.registerModule('initialStates', { state: () => ({ ...structuredClone(this.$store.state) }) }) } 

in the index.js vuex file, i created a resetModule() action :

//index.js export const actions = { resetModule({ state, commit }, namespacedModule) { // acquire initial state const s = state.initialStates[namespacedModule] Object.keys(s).forEach((key) => { commit(`${namespacedModule}/mutate`, { property: `${key}`, with: s[key] }) }) } } 

//YourModuleName.js export const mutations = { mutate(state, payload) { state[payload.property] = payload.with } } 

then, i call the reset action from anywhere and the namespacedModule is reseted :

this.$store.dispatch('resetModule', 'YourModuleName')