Write "for loop" results in a txt file

Question

the script runs fine, but only records the last result in the .txt file. What am i doing wrong?

a= float(input('Insert a: ')) b= float(input('Insert b: ')) for c in range(10,300): d= float(46+(9*a)-(7*c)) e= float(-6+(463*b)+(-1*c)+(0.8*a)+(0.89*d)) print(d) print(e) import sys sys.stdout=open("loop.txt","w") print(d) print(e) sys.stdout.close()

this is because you will write after your loop, so d and e have the last computed values. — daouzli
– daouzli, Commented Jul 21, 2017 at 14:02

Cory Kramer · Accepted Answer · 2017-07-21 14:02:07Z

3

You can write these values inside the loop itself

a= float(input('Insert a: ')) b= float(input('Insert b: ')) with open("loop.txt","w") as f_out: for c in range(10,300): d= float(46+(9*a)-(7*c)) e= float(-6+(463*b)+(-1*c)+(0.8*a)+(0.89*d)) f_out.write('{} {}\n'.format(d, e))

answered Jul 21, 2017 at 14:02

Cory Kramer

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2 Comments

hurtzzPt Over a year ago

works wonderful, can you send me a link with options to format the output?

Cory Kramer Over a year ago

This page is a good reference for string formatting, including precision, padding, sig figs, etc.

Xatyrian · Accepted Answer · 2017-07-21 14:02:01Z

You have to open the stream before doing anything :

import sys sys.stdout = open("loop.txt", "w") a= float(input('Insert a: ')) b= float(input('Insert b: ')) for c in range(10,300): d= float(46+(9*a)-(7*c)) e= float(-6+(463*b)+(-1*c)+(0.8*a)+(0.89*d)) print(d) print(e) sys.stdout.close()

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