Im getting the EOF at the end of the program when i try to run it. i dont really know how to fix it. at first i was getting "if" as an invalid syntax but i think i was able to fix that. thanks for the help
while True:
try: print("Do you want to enter a number?") print("y - yes") print("n - no") choice = int(input("Enter here: ")) if choice == y: print("") count = number for indice in range(1,number + 1, 1): print(number + indice) print("") print("All done") You're missing a except to match try.
Note that there are other issues with your code that will break it, even once you've added except. For example,
if choice == y: ... This should be 'y' instead of y. As it is, y is expected to be a variable, but you're looking to match on the user input 'y' or 'n'.
Also, if you want a string input, then:
choice = int(input("Enter here: ")) will throw an error if you enter, say, 'y':
invalid literal for int() with base 10: 'y' Try taking things one line at a time and making sure you understand what's supposed to happen at each point, and test it. Then put them together.
