I would like to know if I can write a shell script that accepts two arguments simultaneously, one from a file and the another one from stdin. Could you give some example please?.
I trying
while read line do echo "$line" done < "${1}" < "{/dev/stdin}" But this does not work.
You can use cat - or cat /dev/stdin:
while read line; do # your code done < <(cat "$1" -) or
while read line; do # your code done < <(cat "$1" /dev/stdin) or, if you want to read from all files passed through command line as well as stdin, you could do this:
while read line; do # your code done < <(cat "$@" /dev/stdin) See also:
stdin literal to be inferred as stdin?
sh does not support process substitution syntax), or a typo or syntax error on entry. The comment given above is not sufficient to diagnose any of those cases -- and to be clear, the code given here does work when properly and correctly deployed.This topic seems to be helpful here:
{ cat $1; cat; } | while read line do echo "$line" done Or just
cat $1 cat if all you're doing is printing the content
cat "$1", you mean. Otherwise a filename with a space won't be usable. And you only need one instance of cat, as stdin can be referred to as -, as follows: cat "$1" -