subprocess.call on path with space

Question

the string that contains a file looks like this in the console:

>>> target_file 'src//data//annual_filings//ABB Ltd//ABB_ar_2015.pdf'

I got the target_file from a call to os.walk The goal is to build a command to run in subprocess.call Something like:

from subprocess import call cmd_ = r'qpdf-7.0.0/bin/qpdf --password=%s --decrypt %s %s' %('', target_file, target_file) call([cmd_])

I tried different variations, setting shell to either True or False. Replacing the // with /,\ etc. The issue seems to be with the space in the folder (I can not change the folder name).

The python code needs to run on Windows

Why does your path have a double forward slash?

cs95
– cs95

2017-12-14 10:21:21 +00:00
Commented Dec 14, 2017 at 10:21 — cs95
– cs95, Commented Dec 14, 2017 at 10:21

Jean-François Fabre · Accepted Answer · 2017-12-14 10:24:02Z

you have to define cmd_ as a list of arguments not a list with a sole string in it, or subprocess interprets the string as the command (doesn't even try to split the args):

cmd_ = ['qpdf-7.0.0/bin/qpdf','--password=%s'%'','--decrypt',target_file, target_file] call(cmd_)

and leave the quoting to subprocess

As a side note, no need to double the slashes. It works, but that's unnecessary.

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