I'm trying to open a file with spaces in path with subprocess.call function but I can't get it working.
import subprocess subprocess.call(['cmd','/c','start C:/Users/akg/Desktop/file 1.png']) I've tried also
import subprocess file= '"C:/Users/akg/Desktop/file 1.png"' subprocess.call(['cmd','/c','start '+file]) But I still getting this error
1st case : 
, 2nd case 
even spliting the command whenever there is a whitespace is not working
You should put every argument as a separate item in the list passed to subprocess.call:
subprocess.call(['cmd','/c','start', 'C:/Users/akg/Desktop/file 1.png']) 
list2cmdline
The solution that worked for me is to delete the start option as described here : Opening file with spaces in Windows via Command Prompt
import subprocess subprocess.call(['cmd','/c',"C:/Users/akg/Desktop/file 1.png"]) or
subprocess.call(['cmd', '/c', 'start', "", "C:/Users/akg/Desktop/file 1.png"]) Thank you all
subprocess.call(['cmd', '/c', 'start', "", "C:/Users/akg/Desktop/file 1.png"])